Math  /  Data & Statistics

QuestionQuestion 1 1 pts
A random sample of size 20 drawn from a normal population yielded the following results: xˉ=49.2,s=1.33\bar{x}=49.2, s=1.33.
In testing: H0:μ=50H_{0}: \mu=50 versus H1:μ50H_{1}: \mu \neq 50 at a 0.01 level of significance, the decision is to: not reject the null hypothesis. reject the null hypothesis.

Studdy Solution

STEP 1

1. The sample size is n=20 n = 20 .
2. The sample mean is xˉ=49.2 \bar{x} = 49.2 .
3. The sample standard deviation is s=1.33 s = 1.33 .
4. The null hypothesis is H0:μ=50 H_0: \mu = 50 .
5. The alternative hypothesis is H1:μ50 H_1: \mu \neq 50 .
6. The level of significance is α=0.01 \alpha = 0.01 .
7. The population is normally distributed.

STEP 2

1. Calculate the test statistic.
2. Determine the critical value(s) for the test.
3. Make a decision to reject or not reject the null hypothesis based on the test statistic and critical value(s).

STEP 3

Calculate the test statistic using the formula for the t-test:
t=xˉμs/n t = \frac{\bar{x} - \mu}{s / \sqrt{n}}
Substitute the given values:
t=49.2501.33/20 t = \frac{49.2 - 50}{1.33 / \sqrt{20}}
Calculate the value:
t0.80.29752.69 t \approx \frac{-0.8}{0.2975} \approx -2.69

STEP 4

Determine the critical value(s) for a two-tailed test at α=0.01 \alpha = 0.01 with n1=19 n - 1 = 19 degrees of freedom.
Using a t-distribution table or calculator, find the critical values:
tcritical±2.861 t_{\text{critical}} \approx \pm 2.861

STEP 5

Compare the calculated test statistic to the critical values:
Since 2.69 -2.69 is greater than 2.861 -2.861 and less than 2.861 2.861 , it falls within the range of not rejecting the null hypothesis.
Decision: Not reject the null hypothesis.
The decision is to:
Not reject the null hypothesis. \text{Not reject the null hypothesis.}

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