Math  /  Data & Statistics

QuestionProblem Statement: Cumulative Sum for Multiple Queries Problem Description: You are given an array of integers arr[] of size nn. You need to answer multiple range sum queries. For each query, you will be asked to return the sum of elements in the subarray from index I to index rr (both inclusive). You need to process these queries efficiently.
Input: - An array arr[] of integers with size nn. - An integer qq representing the number of queries. - For each query, you are given two integers / and rr, where you need to return the sum of elements in the subarray arr[l...r].
Output: - For each query, print the sum of elements from index I to r (inclusive).
Example Test Cases: Example 1: Input: arr =[1,2,3,4,5]=[1,2,3,4,5] Number of Queries: 3 02 14 04 Output: 6 14 15

Studdy Solution

STEP 1

1. The array arr[] arr[] is zero-indexed.
2. The queries are given as pairs of indices (l,r) (l, r) where 0lr<n 0 \leq l \leq r < n .
3. We need to efficiently compute the sum of elements between indices l l and r r for multiple queries.

STEP 2

1. Preprocess the array to compute prefix sums.
2. Use the prefix sums to efficiently answer each query.

STEP 3

Compute the prefix sum array prefix[] prefix[] where each element prefix[i] prefix[i] is the sum of elements from the start of the array to the i i -th index.
prefix[0]=arr[0] prefix[0] = arr[0]
prefix[i]=prefix[i1]+arr[i]for i=1 to n1 prefix[i] = prefix[i-1] + arr[i] \quad \text{for } i = 1 \text{ to } n-1

STEP 4

For each query (l,r) (l, r) , compute the sum of the subarray arr[l...r] arr[l...r] using the prefix sum array.
If l=0 l = 0 :
Sum=prefix[r] \text{Sum} = prefix[r]
Otherwise:
Sum=prefix[r]prefix[l1] \text{Sum} = prefix[r] - prefix[l-1]
Example Execution:
Given arr=[1,2,3,4,5] arr = [1, 2, 3, 4, 5] , compute the prefix sums:
prefix=[1,3,6,10,15] prefix = [1, 3, 6, 10, 15]
For the queries:
1. Query (0,2) (0, 2) : Sum = prefix[2]=6 prefix[2] = 6
2. Query (1,4) (1, 4) : Sum = prefix[4]prefix[0]=151=14 prefix[4] - prefix[0] = 15 - 1 = 14
3. Query (0,4) (0, 4) : Sum = prefix[4]=15 prefix[4] = 15

Thus, the outputs are:
6,14,15 6, 14, 15

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