Math  /  Calculus

QuestionProblem 2. (1 point) Evaluate the following integral. Use substitution if necessary. Remember to write your answer in terms of the original variable (x)(x). x(8+x2)5dx=112(8+x2)6+C\int x\left(8+x^{2}\right)^{5} d x=\frac{1}{12}\left(8+x^{2}\right)^{6}+C

Studdy Solution

STEP 1

1. The integral is of the form x(8+x2)5dx\int x(8 + x^2)^5 \, dx.
2. We will use substitution to simplify the integration process.
3. The answer must be expressed in terms of the original variable xx.

STEP 2

1. Identify a suitable substitution.
2. Perform the substitution.
3. Integrate with respect to the new variable.
4. Substitute back to the original variable xx.
5. Verify the integration result.

STEP 3

Identify a suitable substitution. Notice that the expression 8+x28 + x^2 is inside the power, and its derivative 2x2x is present (up to a constant factor) in the integrand. This suggests the substitution:
Let u=8+x2 u = 8 + x^2 .
Then, differentiate u u with respect to x x :
dudx=2x \frac{du}{dx} = 2x
This implies:
du=2xdx du = 2x \, dx
So, we can express xdx x \, dx in terms of du du :
xdx=12du x \, dx = \frac{1}{2} du

STEP 4

Perform the substitution in the integral:
x(8+x2)5dx=(8+x2)5xdx \int x(8 + x^2)^5 \, dx = \int (8 + x^2)^5 \cdot x \, dx
Substitute u=8+x2 u = 8 + x^2 and xdx=12du x \, dx = \frac{1}{2} du :
=u512du = \int u^5 \cdot \frac{1}{2} \, du
=12u5du = \frac{1}{2} \int u^5 \, du

STEP 5

Integrate with respect to the new variable u u :
12u5du=12u66+C \frac{1}{2} \int u^5 \, du = \frac{1}{2} \cdot \frac{u^{6}}{6} + C
=112u6+C = \frac{1}{12} u^6 + C

STEP 6

Substitute back to the original variable x x :
Since u=8+x2 u = 8 + x^2 , we have:
112u6+C=112(8+x2)6+C \frac{1}{12} u^6 + C = \frac{1}{12} (8 + x^2)^6 + C

STEP 7

Verify the integration result by differentiating 112(8+x2)6+C\frac{1}{12} (8 + x^2)^6 + C with respect to xx and checking if it equals the original integrand x(8+x2)5x(8 + x^2)^5.
The differentiation process should confirm the correctness of the integration.
The evaluated integral is:
x(8+x2)5dx=112(8+x2)6+C \int x(8 + x^2)^5 \, dx = \frac{1}{12} (8 + x^2)^6 + C

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