QuestionPredicting the products of a neutralization reaction
Predict the products of the reaction below. That is, complete the right-hand side of the chemical equation. Be sure your equation is balanced. $\mathrm{HI}+\mathrm{KOH} \rightarrow$ $\square$

Studdy Solution

STEP 1

What is this asking? We need to complete and balance the chemical equation for the reaction between hydroiodic acid (HI) and potassium hydroxide (KOH). Watch out! Remember that neutralization reactions between an acid and a base typically produce a salt and water.
Don't forget to balance the equation, making sure there are the same number of each type of atom on both sides!

STEP 2

1. Predict the products.
2. Balance the equation.

STEP 3

We have hydroiodic acid ( $\mathrm{HI}$ ), an acid, and potassium hydroxide ( $\mathrm{KOH}$ ), a base.

STEP 4

When an acid reacts with a base, it forms a salt and water.
The salt is formed from the cation of the base ( $\mathrm{K}^{+}$ ) and the anion of the acid ( $\mathrm{I}^{-}$ ).
Water ( $\mathrm{H}_2 \mathrm{O}$ ) is formed from the combination of the hydrogen ion ( $\mathrm{H}^{+}$ ) from the acid and the hydroxide ion ( $\mathrm{OH}^{-}$ ) from the base.

STEP 5

So, our initial unbalanced equation is: $\mathrm{HI} + \mathrm{KOH} \rightarrow \mathrm{KI} + \mathrm{H}_2\mathrm{O}$ Where $\mathrm{KI}$ is potassium iodide (the salt).

STEP 6

Let's see if the number of atoms of each element is the same on both sides of the equation.
We have one $\mathrm{H}$ atom on the left and two on the right.
We have one $\mathrm{I}$ atom on both sides.
We have one $\mathrm{K}$ atom on both sides.
Finally, we have one $\mathrm{O}$ atom on both sides.

STEP 7

The equation is already balanced!
Woohoo! We have the same number of each type of atom on both sides of the equation.

STEP 8

The balanced chemical equation for the reaction is: $\mathrm{HI} + \mathrm{KOH} \rightarrow \mathrm{KI} + \mathrm{H}_2\mathrm{O}$

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QuestionPredicting the products of a neutralization reaction
Predict the products of the reaction below. That is, complete the right-hand side of the chemical equation. Be sure your equation is balanced. $\mathrm{HI}+\mathrm{KOH} \rightarrow$ $\square$

Studdy Solution

STEP 1

STEP 2

1. Predict the products.
2. Balance the equation.

STEP 3

We have hydroiodic acid ( $\mathrm{HI}$ ), an acid, and potassium hydroxide ( $\mathrm{KOH}$ ), a base.

STEP 4

STEP 5

So, our initial unbalanced equation is: $\mathrm{HI} + \mathrm{KOH} \rightarrow \mathrm{KI} + \mathrm{H}_2\mathrm{O}$ Where $\mathrm{KI}$ is potassium iodide (the salt).

STEP 6

Let's see if the number of atoms of each element is the same on both sides of the equation.
We have one $\mathrm{H}$ atom on the left and two on the right.
We have one $\mathrm{I}$ atom on both sides.
We have one $\mathrm{K}$ atom on both sides.
Finally, we have one $\mathrm{O}$ atom on both sides.

STEP 7

The equation is already balanced!
Woohoo! We have the same number of each type of atom on both sides of the equation.

STEP 8

The balanced chemical equation for the reaction is: $\mathrm{HI} + \mathrm{KOH} \rightarrow \mathrm{KI} + \mathrm{H}_2\mathrm{O}$

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QuestionPredicting the products of a neutralization reactionPredict the products of the reaction below. That is, complete the right-hand side of the chemical equation. Be sure your equation is balanced. HI+KOH→\mathrm{HI}+\mathrm{KOH} \rightarrowHI+KOH→ □\square□

Studdy Solution

STEP 1

STEP 2

1. Predict the products.2. Balance the equation.

STEP 3

We have hydroiodic acid (HI\mathrm{HI}HI), an acid, and potassium hydroxide (KOH\mathrm{KOH}KOH), a base.

STEP 4

STEP 5

So, our initial unbalanced equation is: HI+KOH→KI+H2O \mathrm{HI} + \mathrm{KOH} \rightarrow \mathrm{KI} + \mathrm{H}_2\mathrm{O} HI+KOH→KI+H2​O Where KI\mathrm{KI}KI is potassium iodide (the salt).

STEP 6

STEP 7

The equation is already balanced!Woohoo! We have the same number of each type of atom on both sides of the equation.

STEP 8

The balanced chemical equation for the reaction is: HI+KOH→KI+H2O \mathrm{HI} + \mathrm{KOH} \rightarrow \mathrm{KI} + \mathrm{H}_2\mathrm{O} HI+KOH→KI+H2​O

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QuestionPredicting the products of a neutralization reaction
Predict the products of the reaction below. That is, complete the right-hand side of the chemical equation. Be sure your equation is balanced. $\mathrm{HI}+\mathrm{KOH} \rightarrow$ $\square$

1. Predict the products.
2. Balance the equation.

We have hydroiodic acid ( $\mathrm{HI}$ ), an acid, and potassium hydroxide ( $\mathrm{KOH}$ ), a base.

So, our initial unbalanced equation is: $\mathrm{HI} + \mathrm{KOH} \rightarrow \mathrm{KI} + \mathrm{H}_2\mathrm{O}$ Where $\mathrm{KI}$ is potassium iodide (the salt).

The equation is already balanced!
Woohoo! We have the same number of each type of atom on both sides of the equation.

The balanced chemical equation for the reaction is: $\mathrm{HI} + \mathrm{KOH} \rightarrow \mathrm{KI} + \mathrm{H}_2\mathrm{O}$