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Math  /  Data & Statistics

QuestionPos 0 to 1 Pos 1 to 2 Below is a number line marked out in meters. Use the progress of your object along the number line to answer the questions that are Times 4 s 3 s posed.
What was the average speed for the second leg of the trip? Score: 2 A. B. C. D. -0.82 m/s m/s 0.67 -0.67 m/s m/s

Studdy Solution

STEP 1

1. The positions on the number line are given in meters.
2. The time intervals for each leg of the trip are given in seconds.
3. Average speed is calculated as the total distance traveled divided by the total time taken.

STEP 2

1. Determine the distance traveled during the second leg of the trip.
2. Calculate the average speed for the second leg.

STEP 3

Identify the initial and final positions for the second leg of the trip:
- Initial position (Pos 1): −5-5 meters - Final position (Pos 2): −7-7 meters

STEP 4

Calculate the distance traveled during the second leg:
Distance=Final position−Initial position=−7−(−5)=−2 meters \text{Distance} = \text{Final position} - \text{Initial position} = -7 - (-5) = -2 \text{ meters}

STEP 5

Identify the time taken for the second leg of the trip:
- Time: 33 seconds

STEP 6

Calculate the average speed for the second leg:
Average speed=DistanceTime=−2 meters3 seconds=−0.67 m/s \text{Average speed} = \frac{\text{Distance}}{\text{Time}} = \frac{-2 \text{ meters}}{3 \text{ seconds}} = -0.67 \text{ m/s}
The average speed for the second leg of the trip is:
−0.67 m/s \boxed{-0.67 \text{ m/s}}

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