Math  /  Algebra

QuestionPoint SS is the midpoint of line RT. RS is 3x+203 x+20 and RT is 12x1012 x-10. What is the length of RS? Round your answer to the nearest hundredth if necessary. Your Answer:
Answer
Question 3 (2 points)

Studdy Solution

STEP 1

1. Point S S is the midpoint of line RT RT .
2. RS=3x+20 RS = 3x + 20 .
3. RT=12x10 RT = 12x - 10 .
4. We need to find the length of RS RS .

STEP 2

1. Understand the relationship between the segments.
2. Set up an equation using the midpoint property.
3. Solve the equation for x x .
4. Substitute x x back into the expression for RS RS to find its length.

STEP 3

Understand the relationship between the segments. Since S S is the midpoint of RT RT , we know that RS=ST RS = ST .

STEP 4

Set up an equation using the midpoint property. Since S S is the midpoint, RS=ST RS = ST and RT=RS+ST=2×RS RT = RS + ST = 2 \times RS .
Therefore, RT=2×(3x+20) RT = 2 \times (3x + 20) .

STEP 5

Solve the equation for x x .
Substitute the expression for RT RT into the equation:
12x10=2×(3x+20) 12x - 10 = 2 \times (3x + 20)
Simplify the right side:
12x10=6x+40 12x - 10 = 6x + 40
Subtract 6x 6x from both sides:
6x10=40 6x - 10 = 40
Add 10 to both sides:
6x=50 6x = 50
Divide by 6:
x=506 x = \frac{50}{6}
x8.33 x \approx 8.33

STEP 6

Substitute x x back into the expression for RS RS to find its length.
RS=3x+20 RS = 3x + 20
RS=3(8.33)+20 RS = 3(8.33) + 20
RS=24.99+20 RS = 24.99 + 20
RS44.99 RS \approx 44.99
The length of RS RS is approximately 44.99 \boxed{44.99} .

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