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QuestionWhat is the weight in grams of 1 mole of silver atoms, given that one silver atom weighs 1.79×10−221.79 \times 10^{-22} grams?

Studdy Solution

STEP 1

Assumptions1. The average weight of a single silver atom is 1.79×10−221.79 \times10^{-22} grams. .1 mole of any substance contains Avogadro's number of particles, which is approximately 6.022×10236.022 \times10^{23} particles.

STEP 2

We need to find the weight of1 mole of silver atoms. We can do this by multiplying the weight of a single silver atom by Avogadro's number.
Weight of 1 mole of silver=Weight of a single silver atom×Avogadro′s numberWeight\, of\,1\, mole\, of\, silver = Weight\, of\, a\, single\, silver\, atom \times Avogadro's\, number

STEP 3

Now, plug in the given values for the weight of a single silver atom and Avogadro's number to calculate the weight of1 mole of silver.
Weight of 1 mole of silver=1.79×10−22 grams×6.022×1023Weight\, of\,1\, mole\, of\, silver =1.79 \times10^{-22}\, grams \times6.022 \times10^{23}

STEP 4

Calculate the weight of1 mole of silver atoms.
Weight of 1 mole of silver=1.79×10−22 grams×6.022×1023=107.794 gramsWeight\, of\,1\, mole\, of\, silver =1.79 \times10^{-22}\, grams \times6.022 \times10^{23} =107.794\, gramsSo,1 mole of silver atoms weighs approximately107.794 grams.

STEP 5

Now, let's check the periodic table. The atomic weight of silver (Ag) on the periodic table is approximately107.87 grams/mole.
The calculated weight of1 mole of silver atoms is very close to the atomic weight of silver on the periodic table, which confirms our calculation.

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