QuestionSolve the equation: $\frac{1}{2} n + 3 = 6$ .

Studdy Solution

STEP 1

Assumptions1. The equation given is $\frac{1}{} n+3=6$ . We are solving for the variable $n$

STEP 2

We start by isolating the term with $n$ on one side of the equation. We can do this by subtracting $$ from both sides of the equation.
$\frac{1}{2} n+-=6-$

STEP 3

Perform the subtraction operation on both sides.
$\frac{1}{2} n=6-3$

STEP 4

Calculate the result on the right side of the equation.
$\frac{1}{2} n=3$

STEP 5

To solve for $n$ , we need to get rid of the fraction $\frac{1}{2}$ in front of $n$ . We can do this by multiplying both sides of the equation by $2$ .
$2 \cdot \frac{1}{2} n=2 \cdot3$

STEP 6

Perform the multiplication operation on both sides.
$n=2 \cdot3$

STEP 7

Calculate the result on the right side of the equation.
$n=6$ So, the solution to the equation $\frac{1}{2} n+3=6$ is $n=6$ .

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QuestionSolve the equation: $\frac{1}{2} n + 3 = 6$ .

Studdy Solution

STEP 1

Assumptions1. The equation given is $\frac{1}{} n+3=6$ . We are solving for the variable $n$

STEP 2

We start by isolating the term with $n$ on one side of the equation. We can do this by subtracting $$ from both sides of the equation.
$\frac{1}{2} n+-=6-$

STEP 3

Perform the subtraction operation on both sides.
$\frac{1}{2} n=6-3$

STEP 4

Calculate the result on the right side of the equation.
$\frac{1}{2} n=3$

STEP 5

To solve for $n$ , we need to get rid of the fraction $\frac{1}{2}$ in front of $n$ . We can do this by multiplying both sides of the equation by $2$ .
$2 \cdot \frac{1}{2} n=2 \cdot3$

STEP 6

Perform the multiplication operation on both sides.
$n=2 \cdot3$

STEP 7

Calculate the result on the right side of the equation.
$n=6$ So, the solution to the equation $\frac{1}{2} n+3=6$ is $n=6$ .

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QuestionSolve the equation: 12n+3=6\frac{1}{2} n + 3 = 621​n+3=6.

Studdy Solution

STEP 1

Assumptions1. The equation given is 1n+3=6\frac{1}{} n+3=61​n+3=6 . We are solving for the variable nnn

STEP 2

We start by isolating the term with nnn on one side of the equation. We can do this by subtracting $$ from both sides of the equation.12n+−=6−\frac{1}{2} n+-=6-21​n+−=6−

STEP 3

Perform the subtraction operation on both sides.12n=6−3\frac{1}{2} n=6-321​n=6−3

STEP 4

Calculate the result on the right side of the equation.12n=3\frac{1}{2} n=321​n=3

STEP 5

To solve for nnn, we need to get rid of the fraction 12\frac{1}{2}21​ in front of nnn. We can do this by multiplying both sides of the equation by 222.2⋅12n=2⋅32 \cdot \frac{1}{2} n=2 \cdot32⋅21​n=2⋅3

STEP 6

Perform the multiplication operation on both sides.n=2⋅3n=2 \cdot3n=2⋅3

STEP 7

Calculate the result on the right side of the equation.n=6n=6n=6So, the solution to the equation 12n+3=6\frac{1}{2} n+3=621​n+3=6 is n=6n=6n=6.

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QuestionSolve the equation: $\frac{1}{2} n + 3 = 6$ .

Assumptions1. The equation given is $\frac{1}{} n+3=6$ . We are solving for the variable $n$

We start by isolating the term with $n$ on one side of the equation. We can do this by subtracting $$ from both sides of the equation.
$\frac{1}{2} n+-=6-$

Perform the subtraction operation on both sides.
$\frac{1}{2} n=6-3$

Calculate the result on the right side of the equation.
$\frac{1}{2} n=3$

To solve for $n$ , we need to get rid of the fraction $\frac{1}{2}$ in front of $n$ . We can do this by multiplying both sides of the equation by $2$ .
$2 \cdot \frac{1}{2} n=2 \cdot3$

Perform the multiplication operation on both sides.
$n=2 \cdot3$

Calculate the result on the right side of the equation.
$n=6$ So, the solution to the equation $\frac{1}{2} n+3=6$ is $n=6$ .