Math

QuestionCalculate the sum: =98+91=\frac{9}{8}+\frac{9}{1}.

Studdy Solution

STEP 1

Assumptions1. The problem is a simple addition of two fractions. . The fractions are 98\frac{9}{8} and 91\frac{9}{1}.

STEP 2

To add fractions, we need to have a common denominator. In this case, the denominators are8 and1. The least common multiple (LCM) of8 and1 is8.

STEP 3

Now, we rewrite the fractions with the common denominator.
98=98\frac{9}{8} = \frac{9}{8}Since1 divides into8 exactly8 times, we multiply both the numerator and denominator of 91\frac{9}{1} by8 to get the equivalent fraction with8 as the denominator.
91=9×81×8=728\frac{9}{1} = \frac{9 \times8}{1 \times8} = \frac{72}{8}

STEP 4

Now, we can add the two fractions.
98+728\frac{9}{8} + \frac{72}{8}

STEP 5

Add the numerators and keep the denominator.
9+728\frac{9 +72}{8}

STEP 6

Calculate the numerator.
818\frac{81}{8}This is the final answer. However, it can be simplified further.

STEP 7

implify the fraction by dividing the numerator by the denominator.
81=10.125\frac{81}{} =10.125So, =9+91=10.125=\frac{9}{}+\frac{9}{1}=10.125.

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