Math

QuestionCalculate the expression using the order of operations: 42+6[12÷(59)]-4^{2}+6[12 \div(5-9)]. What is the result?

Studdy Solution

STEP 1

Assumptions1. We are given the expression 4+6[12÷(59)]-4^{}+6[12 \div(5-9)] . We need to solve this expression using the order of operations, which is Parentheses, Exponents, Multiplication and Division (from left to right), Addition and Subtraction (from left to right). This is often abbreviated as PEMAS.

STEP 2

First, we need to solve the operation inside the parentheses (5-9).
42+6[12÷(59)]=42+6[12÷(4)]-4^{2}+6[12 \div(5-9)] = -4^{2}+6[12 \div(-4)]

STEP 3

Next, we perform the division operation inside the brackets.
2+6[12÷()]=2+6[3]-^{2}+6[12 \div(-)] = -^{2}+6[-3]

STEP 4

After that, we perform the multiplication operation.
42+6[3]=42+(18)-4^{2}+6[-3] = -4^{2}+(-18)

STEP 5

Then, we calculate the exponent.
42+(18)=16+(18)-4^{2}+(-18) = -16+(-18)

STEP 6

Finally, we perform the addition operation.
16+(18)=34-16+(-18) = -34So, the value of the given expression is -34.

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