Math

QuestionNanda and Lane sold 160 homes, with Nanda selling 4 times Lane's homes. How many did each sell?

Studdy Solution

STEP 1

Assumptions1. Nanda and Lane together sold160 homes in total. . Nanda sold4 times as many homes as Lane.

STEP 2

Let's denote the number of homes sold by Lane as xx. According to the problem, Nanda sold4 times as many homes as Lane. So, we can denote the number of homes sold by Nanda as 4x4x.

STEP 3

We know that the total number of homes sold by both Nanda and Lane is160. So we can set up the following equationx+x=160x +x =160

STEP 4

implify the equation by combining like terms.
x=160x =160

STEP 5

To find the value of xx, we need to divide both sides of the equation by5.
x=1605x = \frac{160}{5}

STEP 6

Calculate the value of xx.
x=1605=32x = \frac{160}{5} =32So, Lane sold32 homes.

STEP 7

Now, let's find out how many homes Nanda sold. We know that Nanda sold4 times as many homes as Lane. So, we can calculate the number of homes sold by Nanda as followsandashomes=4xanda's\, homes =4x

STEP 8

Plug in the value of xx (the number of homes sold by Lane) into the equation.
andashomes=4times32anda's\, homes =4 \\times32

STEP 9

Calculate the number of homes sold by Nanda.
andashomes=4times32=128anda's\, homes =4 \\times32 =128So, Nanda sold128 homes.
Lane sold32 homes and Nanda sold128 homes.

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