Math

Question Multiply 2i(6i+6)2 i(-6 i+6) and write the expression in standard form. Choose the correct answer.

Studdy Solution

STEP 1

Assumptions
1. We are given the expression 2i(6i+6)2i(-6i + 6).
2. We need to multiply the terms and write the expression in standard form.
3. The standard form for a complex number is a+bia + bi, where aa and bb are real numbers, and ii is the imaginary unit with the property i2=1i^2 = -1.

STEP 2

Distribute the 2i2i across the terms inside the parentheses.
2i(6i+6)=2i(6i)+2i62i(-6i + 6) = 2i \cdot (-6i) + 2i \cdot 6

STEP 3

Multiply the coefficients and apply the imaginary unit property i2=1i^2 = -1.
2i(6i)=12i22i \cdot (-6i) = -12i^2

STEP 4

Multiply the second set of terms.
2i6=12i2i \cdot 6 = 12i

STEP 5

Combine the results from STEP_3 and STEP_4.
12i2+12i-12i^2 + 12i

STEP 6

Substitute i2i^2 with 1-1 as per the property of the imaginary unit.
12(1)+12i-12(-1) + 12i

STEP 7

Simplify the expression by multiplying 12-12 by 1-1.
12+12i12 + 12i
The expression in standard form is 12+12i12 + 12i.
The correct answer is D. 12+12i12+12i.

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