QuestionMultiply or divide these measurements, ensuring correct significant digits:
$2.09 \frac{\mathrm{mol}}{\mathrm{L}} \times 4.60 \mathrm{~L}=\square \mathrm{mol}$ ,
$20.9 \mathrm{~cm} \times 22 \mathrm{~cm}=\square \mathrm{cm}^{2}$ ,
$137.1 \mathrm{~g} \div 0.43 \mathrm{~mL}=\square \frac{\mathrm{g}}{\mathrm{mL}}$ .

Studdy Solution

STEP 1

Assumptions1. The multiplication and division operations should be performed as indicated. . The number of significant digits in the result should match the least number of significant digits in the given measurements.

STEP 2

Let's perform the first operation. Multiply the given measurements.
$2.09 \frac{mol}{} \times4.60 L$

STEP 3

Perform the multiplication.
$2.09 \frac{mol}{} \times.60 L =9.614 mol$

STEP 4

We need to round the result to the correct number of significant digits. Both of the given measurements have three significant digits, so our result should also have three significant digits.
$9.614 mol \approx9.61 mol$

STEP 5

Now, let's perform the second operation. Multiply the given measurements.
$20.9 cm \times22 cm$

STEP 6

Perform the multiplication.
$20.9 cm \times22 cm =460.8 cm^2$

STEP 7

We need to round the result to the correct number of significant digits. The measurement22 cm has two significant digits, which is the least number of significant digits in the given measurements. Therefore, our result should also have two significant digits.
$460. cm^2 \approx460 cm^2$

STEP 8

Finally, let's perform the third operation. Divide the given measurements.
$137.1 g \div0.43 mL$

STEP 9

Perform the division.
$137. g \div.43 mL =318.8372093023256 \frac{g}{m}$

STEP 10

We need to round the result to the correct number of significant digits. The measurement0.43 mL has two significant digits, which is the least number of significant digits in the given measurements. Therefore, our result should also have two significant digits.
$318.8372093023256 \frac{g}{m} \approx320 \frac{g}{m}$ So, the results of the operations are $2.09 \frac{mol}{} \times4.60 L =9.61 mol$ $20.9 cm \times22 cm =460 cm^2$ $137. g \div0.43 mL =320 \frac{g}{m}$

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Studdy Solution

STEP 1

Assumptions1. The multiplication and division operations should be performed as indicated. . The number of significant digits in the result should match the least number of significant digits in the given measurements.

STEP 2

Let's perform the first operation. Multiply the given measurements.
$2.09 \frac{mol}{} \times4.60 L$

STEP 3

Perform the multiplication.
$2.09 \frac{mol}{} \times.60 L =9.614 mol$

STEP 4

We need to round the result to the correct number of significant digits. Both of the given measurements have three significant digits, so our result should also have three significant digits.
$9.614 mol \approx9.61 mol$

STEP 5

Now, let's perform the second operation. Multiply the given measurements.
$20.9 cm \times22 cm$

STEP 6

Perform the multiplication.
$20.9 cm \times22 cm =460.8 cm^2$

STEP 7

We need to round the result to the correct number of significant digits. The measurement22 cm has two significant digits, which is the least number of significant digits in the given measurements. Therefore, our result should also have two significant digits.
$460. cm^2 \approx460 cm^2$

STEP 8

Finally, let's perform the third operation. Divide the given measurements.
$137.1 g \div0.43 mL$

STEP 9

Perform the division.
$137. g \div.43 mL =318.8372093023256 \frac{g}{m}$

STEP 10

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Studdy Solution

STEP 1

Assumptions1. The multiplication and division operations should be performed as indicated. . The number of significant digits in the result should match the least number of significant digits in the given measurements.

STEP 2

Let's perform the first operation. Multiply the given measurements.2.09mol×4.60L2.09 \frac{mol}{} \times4.60 L2.09mol​×4.60L

STEP 3

Perform the multiplication.2.09mol×.60L=9.614mol2.09 \frac{mol}{} \times.60 L =9.614 mol2.09mol​×.60L=9.614mol

STEP 4

We need to round the result to the correct number of significant digits. Both of the given measurements have three significant digits, so our result should also have three significant digits.9.614mol≈9.61mol9.614 mol \approx9.61 mol9.614mol≈9.61mol

STEP 5

Now, let's perform the second operation. Multiply the given measurements.20.9cm×22cm20.9 cm \times22 cm20.9cm×22cm

STEP 6

Perform the multiplication.20.9cm×22cm=460.8cm220.9 cm \times22 cm =460.8 cm^220.9cm×22cm=460.8cm2

STEP 7

STEP 8

Finally, let's perform the third operation. Divide the given measurements.137.1g÷0.43mL137.1 g \div0.43 mL137.1g÷0.43mL

STEP 9

Perform the division.137.g÷.43mL=318.8372093023256gm137. g \div.43 mL =318.8372093023256 \frac{g}{m}137.g÷.43mL=318.8372093023256mg​

STEP 10

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Studdy solves anything!

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

Let's perform the first operation. Multiply the given measurements.
$2.09 \frac{mol}{} \times4.60 L$

Perform the multiplication.
$2.09 \frac{mol}{} \times.60 L =9.614 mol$

We need to round the result to the correct number of significant digits. Both of the given measurements have three significant digits, so our result should also have three significant digits.
$9.614 mol \approx9.61 mol$

Now, let's perform the second operation. Multiply the given measurements.
$20.9 cm \times22 cm$

Perform the multiplication.
$20.9 cm \times22 cm =460.8 cm^2$

Finally, let's perform the third operation. Divide the given measurements.
$137.1 g \div0.43 mL$

Perform the division.
$137. g \div.43 mL =318.8372093023256 \frac{g}{m}$