Math

QuestionMrs. Bennett swims 50 feet in 12.3 seconds. How many yards can she swim in 40 seconds?

Studdy Solution

STEP 1

Assumptions1. Mrs. Bennett swims at a constant speed. . The distance Mrs. Bennett swims in12.3 seconds is50 feet.
3. We want to find out how many yards she can swim in40 seconds. 4.1 yard =3 feet.

STEP 2

First, we need to find the speed of Mrs. Bennett in feet per second. We can do this by dividing the distance she swims by the time it takes.
Speed=DistanceTimeSpeed = \frac{Distance}{Time}

STEP 3

Now, plug in the given values for the distance and time to calculate the speed.
Speed=50feet12.3secondsSpeed = \frac{50\, feet}{12.3\, seconds}

STEP 4

Calculate the speed of Mrs. Bennett.
Speed=5012.34.07feet/secondSpeed = \frac{50}{12.3} \approx4.07\, feet/second

STEP 5

Now that we have the speed of Mrs. Bennett, we can find out how far she can swim in40 seconds. We can do this by multiplying her speed by the time.
Distance=Speed×TimeDistance = Speed \times Time

STEP 6

Plug in the values for the speed and the time to calculate the distance.
Distance=4.07feet/second×40secondsDistance =4.07\, feet/second \times40\, seconds

STEP 7

Calculate the distance Mrs. Bennett can swim in40 seconds.
Distance=4.07×40=162.feetDistance =4.07 \times40 =162.\, feet

STEP 8

Now that we have the distance in feet, we need to convert this to yards. We can do this by dividing the distance in feet by the number of feet in a yard.
Distance=DistanceinfeetNumberoffeetinayardDistance = \frac{Distance\, in\, feet}{Number\, of\, feet\, in\, a\, yard}

STEP 9

Plug in the values for the distance in feet and the number of feet in a yard to calculate the distance in yards.
Distance=162.8feet3feet/yardDistance = \frac{162.8\, feet}{3\, feet/yard}

STEP 10

Calculate the distance Mrs. Bennett can swim in40 seconds in yards.
Distance=162.8354.27yardsDistance = \frac{162.8}{3} \approx54.27\, yardsMrs. Bennett can swim approximately54.27 yards in40 seconds.

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