Math

QuestionFind the value of mm for the continuous function f(x)={mx8 if x<7x2+10x1 if x7f(x)=\left\{\begin{array}{ll}m x-8 & \text { if } \quad x<-7 \\ x^{2}+10 x-1 & \text { if } \quad x \geq-7\end{array}\right.

Studdy Solution

STEP 1

Assumptions1. The function f(x)f(x) is given by f(x)={mx8 if x<7x+10x1 if x7f(x)=\left\{\begin{array}{ll}m x-8 & \text { if } \quad x<-7 \\ x^{}+10 x-1 & \text { if } \quad x \geq-7\end{array}\right.. The function f(x)f(x) is continuous everywhere.

STEP 2

For a piecewise function to be continuous at a point where the function definition changes (in this case, x=7x=-7), the two pieces of the function must meet at that point. This means that the value of the function at x=7x=-7 must be the same whether we use the first piece (mx8mx-8) or the second piece (x2+10x1x^{2}+10x-1).
So, we can set up the equationm(7)8=(7)2+10(7)1m(-7) -8 = (-7)^2 +10(-7) -1

STEP 3

Now, we simplify the equation to solve for mm.
7m8=49701-7m -8 =49 -70 -1

STEP 4

implify the right side of the equation.
7m8=22-7m -8 = -22

STEP 5

Add8 to both sides of the equation to isolate the term with mm on one side.
7m=22+8-7m = -22 +8

STEP 6

implify the right side of the equation.
m=14-m = -14

STEP 7

Finally, divide both sides of the equation by -7 to solve for mm.
m=14/7m = -14 / -7

STEP 8

implify the right side of the equation to find the value of mm.
m=2m =2So, for the function f(x)f(x) to be continuous everywhere, mm must be equal to2.

Was this helpful?

Studdy solves anything!

banner

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

ParentsInfluencer programContactPolicyTerms
TwitterInstagramFacebookTikTokDiscord