Math  /  Algebra

Question(x+3)3(x+3)^{3}

Studdy Solution

STEP 1

What is this asking? We need to expand the expression (x+3)3(x+3)^3, which means multiplying (x+3)(x+3) by itself three times! Watch out! Don't forget to multiply *each* term in one set of parentheses by *each* term in the other set of parentheses.
It's easy to miss a term!
Also, don't confuse this with x3+33x^3 + 3^3, which is totally different.

STEP 2

1. Expand the first two factors
2. Multiply the result by the third factor
3. Simplify and combine like terms

STEP 3

Let's **start** by multiplying the first two factors of (x+3)3(x+3)^3, which are (x+3)(x+3) and (x+3)(x+3).

STEP 4

We'll use the **FOIL method** (First, Outer, Inner, Last) to multiply these binomials: (x+3)(x+3)=xx+x3+3x+33(x+3) \cdot (x+3) = x \cdot x + x \cdot 3 + 3 \cdot x + 3 \cdot 3

STEP 5

This simplifies to: x2+3x+3x+9=x2+6x+9x^2 + 3x + 3x + 9 = x^2 + 6x + 9 So, the product of the first two factors is x2+6x+9x^2 + 6x + 9.

STEP 6

Now, we need to multiply the result from the previous step, x2+6x+9x^2 + 6x + 9, by the third factor, (x+3)(x+3).

STEP 7

We'll distribute each term of x2+6x+9x^2 + 6x + 9 to each term of (x+3)(x+3): (x2+6x+9)(x+3)=x2(x+3)+6x(x+3)+9(x+3)(x^2 + 6x + 9)(x+3) = x^2(x+3) + 6x(x+3) + 9(x+3)

STEP 8

Now, let's expand each part of this expression: x2(x+3)=x3+3x2x^2(x+3) = x^3 + 3x^2 6x(x+3)=6x2+18x6x(x+3) = 6x^2 + 18x9(x+3)=9x+279(x+3) = 9x + 27

STEP 9

Putting it all together, we get: x3+3x2+6x2+18x+9x+27x^3 + 3x^2 + 6x^2 + 18x + 9x + 27

STEP 10

We have some like terms we can combine.
Specifically, we have 3x23x^2 and 6x26x^2, and we also have 18x18x and 9x9x.

STEP 11

Combining these like terms gives us: x3+(3x2+6x2)+(18x+9x)+27=x3+9x2+27x+27x^3 + (3x^2 + 6x^2) + (18x + 9x) + 27 = x^3 + 9x^2 + 27x + 27

STEP 12

Our **final answer** is x3+9x2+27x+27x^3 + 9x^2 + 27x + 27!

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