Math

QuestionCombine lc+ldcdcd\frac{l}{c}+\frac{l}{d}-\frac{c-d}{c d} into one simplified fraction.

Studdy Solution

STEP 1

Assumptions1. The given expression is lc+ldcdcd\frac{l}{c}+\frac{l}{d}-\frac{c-d}{c d}. . We need to simplify this expression to a single fraction.

STEP 2

First, we notice that the first two terms have a common numerator. We can combine these two terms into a single fraction. The common denominator will be the product of the two denominators.
lc+ld=ld+lccd\frac{l}{c}+\frac{l}{d} = \frac{l \cdot d + l \cdot c}{c \cdot d}

STEP 3

Next, we simplify the numerator of the new fraction by factoring out the common factor, which is ll.
ld+lccd=l(c+d)cd\frac{l \cdot d + l \cdot c}{c \cdot d} = \frac{l(c + d)}{c \cdot d}

STEP 4

Now, we rewrite the entire expression, replacing the first two terms with the new fraction we just calculated.
l(c+d)cdcdcd\frac{l(c + d)}{c \cdot d} - \frac{c-d}{c \cdot d}

STEP 5

We notice that the two fractions have the same denominator. This means we can combine them into a single fraction.
l(c+d)cdcdcd=l(c+d)(cd)cd\frac{l(c + d)}{c \cdot d} - \frac{c-d}{c \cdot d} = \frac{l(c + d) - (c - d)}{c \cdot d}

STEP 6

Next, we simplify the numerator of the new fraction.
l(c+d)(cd)cd=lc+ldc+dcd\frac{l(c + d) - (c - d)}{c \cdot d} = \frac{lc + ld - c + d}{c \cdot d}

STEP 7

Now, we group the terms in the numerator.
lc+ldc+dcd=lcc+ld+dcd\frac{lc + ld - c + d}{c \cdot d} = \frac{lc - c + ld + d}{c \cdot d}

STEP 8

Next, we factor out the common factors from the grouped terms.
lcc+ld+dcd=c(l1)+d(l+1)cd\frac{lc - c + ld + d}{c \cdot d} = \frac{c(l -1) + d(l +1)}{c \cdot d}So, the expression lc+ldcdcd\frac{l}{c}+\frac{l}{d}-\frac{c-d}{c d} simplifies to c(l1)+d(l+1)cd\frac{c(l -1) + d(l +1)}{c \cdot d}.

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