Math

QuestionFill in the table using f(x)=x4f(x)=\sqrt{x-4}. For x=0x=0, 4, 13, and 85, find f(x)f(x) or state "Not a real number".

Studdy Solution

STEP 1

Assumptions1. The function is given by f(x)=x4f(x)=\sqrt{x-4} . The function is defined for all real numbers xx such that x4x \geq4
3. For x<4x <4, the function is not a real number

STEP 2

We need to find the value of f(x)f(x) when x=13x=13. We can do this by substituting x=13x=13 into the function.
f(13)=134f(13) = \sqrt{13-4}

STEP 3

Calculate the value inside the square root.
f(13)=9f(13) = \sqrt{9}

STEP 4

Calculate the square root of9.
f(13)=3f(13) =3

STEP 5

We need to find the value of f(x)f(x) when x=85x=85. We can do this by substituting x=85x=85 into the function.
f(85)=854f(85) = \sqrt{85-4}

STEP 6

Calculate the value inside the square root.
f(85)=81f(85) = \sqrt{81}

STEP 7

Calculate the square root of81.
f(85)=9f(85) =9So, the completed table is\begin{tabular}{|c|c|} \hlinexx & f(x)f(x) \\ \hline0 & Not a real number \\ \hline4 &0 \\ \hline13 &3 \\ \hline85 &9 \\ \hline\end{tabular}

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