Math  /  Algebra

QuestionKitchen Korner produces refrigerators, dishwashers, and stoves at three different factories. The table gives the number of each product produced at each factory per day. Kitchen Korner receives an order for 166 refrigerators, 210 dishwashers, and 172 ovens. How many days should each plant be scheduled to fill this order? \begin{tabular}{|l|c|c|c|} \hline Appliance & Factory A & Factory B & Factory C \\ \hline Refrigerators & 8 & 10 & 14 \\ Dishwashers & 16 & 12 & 10 \\ Stoves & 10 & 18 & 6 \\ \hline \end{tabular}

Studdy Solution

STEP 1

1. Each factory produces a fixed number of each appliance per day.
2. The goal is to determine the number of days each factory should operate to meet the exact order requirements.
3. We can use a system of linear equations to solve the problem.

STEP 2

1. Define variables for the number of days each factory operates.
2. Set up equations based on the production rates and order requirements.
3. Solve the system of equations.

STEP 3

Define variables: Let x x be the number of days Factory A operates, y y be the number of days Factory B operates, and z z be the number of days Factory C operates.

STEP 4

Set up equations based on the production rates and order requirements:
For refrigerators: 8x+10y+14z=166 8x + 10y + 14z = 166
For dishwashers: 16x+12y+10z=210 16x + 12y + 10z = 210
For stoves: 10x+18y+6z=172 10x + 18y + 6z = 172

STEP 5

Solve the system of equations using substitution or elimination methods.
First, simplify the equations if possible. Let's start with the first two equations:
1. 8x+10y+14z=166 8x + 10y + 14z = 166
2. 16x+12y+10z=210 16x + 12y + 10z = 210

Multiply the first equation by 2 to align the coefficients of x x :
16x+20y+28z=332 16x + 20y + 28z = 332
Subtract the second equation from this new equation:
(16x+20y+28z)(16x+12y+10z)=332210 (16x + 20y + 28z) - (16x + 12y + 10z) = 332 - 210
8y+18z=122 8y + 18z = 122

STEP 6

Now, solve for y y in terms of z z :
8y=12218z 8y = 122 - 18z
y=12218z8 y = \frac{122 - 18z}{8}
Substitute y y in terms of z z into the third equation:
10x+18(12218z8)+6z=172 10x + 18\left(\frac{122 - 18z}{8}\right) + 6z = 172
Simplify and solve for x x and z z :
10x+2196324z8+6z=172 10x + \frac{2196 - 324z}{8} + 6z = 172
Multiply through by 8 to clear the fraction:
80x+2196324z+48z=1376 80x + 2196 - 324z + 48z = 1376
80x276z=13762196 80x - 276z = 1376 - 2196
80x276z=820 80x - 276z = -820

STEP 7

Solve for x x in terms of z z :
80x=276z820 80x = 276z - 820
x=276z82080 x = \frac{276z - 820}{80}
Now, substitute both expressions for x x and y y in terms of z z into the first equation to find z z .
8(276z82080)+10(12218z8)+14z=166 8\left(\frac{276z - 820}{80}\right) + 10\left(\frac{122 - 18z}{8}\right) + 14z = 166
Simplify and solve for z z :
2208z656080+1220180z8+14z=166 \frac{2208z - 6560}{80} + \frac{1220 - 180z}{8} + 14z = 166
Clear fractions by multiplying through by 80:
2208z6560+10(1220180z)+1120z=13280 2208z - 6560 + 10(1220 - 180z) + 1120z = 13280
2208z6560+122001800z+1120z=13280 2208z - 6560 + 12200 - 1800z + 1120z = 13280
Combine like terms:
1528z+5640=13280 1528z + 5640 = 13280
1528z=132805640 1528z = 13280 - 5640
1528z=7640 1528z = 7640
z=76401528 z = \frac{7640}{1528}
z=5 z = 5

STEP 8

Substitute z=5 z = 5 back into the expressions for x x and y y :
x=276(5)82080 x = \frac{276(5) - 820}{80}
x=138082080 x = \frac{1380 - 820}{80}
x=56080 x = \frac{560}{80}
x=7 x = 7
y=12218(5)8 y = \frac{122 - 18(5)}{8}
y=122908 y = \frac{122 - 90}{8}
y=328 y = \frac{32}{8}
y=4 y = 4
The number of days each plant should be scheduled to fill the order is: Factory A: 7 days, Factory B: 4 days, Factory C: 5 days.

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