QuestionJacob painted a square mural. The hallway mural is 6 ft longer and 2 ft shorter. If $x=8$ , find the area expression.

Studdy Solution

STEP 1

Assumptions1. The mural in the classroom is a square, so all sides are equal in length. Let $x$ represent this length. . The mural in the hallway is a rectangle, whose length is6 feet longer and whose width is feet shorter than the classroom mural.
3. The area of a rectangle is calculated by multiplying its length and width.

STEP 2

We need to write an expression that represents the two binomials we would multiply to find the area of the hallway mural. The length of the hallway mural is $x +6$ (since it's6 feet longer than the classroom mural) and the width is $x -2$ (since it's2 feet shorter).
$Area = (x +6)(x -2)$

STEP 3

Now, we need to plug in the given value for $x$ (the side length of the classroom mural) into our expression to find the area of the hallway mural.
$Area = (8 +6)(8 -2)$

STEP 4

implify the expression.
$Area = (14)(6)$

STEP 5

Calculate the area of the hallway mural.
$Area =14 \\times =84$ The correct answer is D. $(x+)(x-2) ;84$ square feet.

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