QuestionCheck if $1$ is a solution to the equation $7x + 3 = 6x - 5$ .

Studdy Solution

STEP 1

Assumptions1. The equation to be solved is $7x +3 =6x -5$ . We are checking if $x =1$ is a solution to the equation

STEP 2

To check if $x =1$ is a solution, we substitute $x =1$ into the equation and see if both sides are equal.
$7(1) + =6(1) -5$

STEP 3

Calculate the left side of the equation.
$7(1) +3 =7 +3 =10$

STEP 4

Calculate the right side of the equation.
$6(1) - =6 - =1$

STEP 5

Compare the left and right sides of the equation. If they are equal, then $x =1$ is a solution. If they are not equal, then $x =1$ is not a solution.
Since $10 \neq1$ , $x =1$ is not a solution to the equation $7x +3 =x -5$ .
So, the answer is "No".

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QuestionCheck if $1$ is a solution to the equation $7x + 3 = 6x - 5$ .

Studdy Solution

STEP 1

Assumptions1. The equation to be solved is $7x +3 =6x -5$ . We are checking if $x =1$ is a solution to the equation

STEP 2

To check if $x =1$ is a solution, we substitute $x =1$ into the equation and see if both sides are equal.
$7(1) + =6(1) -5$

STEP 3

Calculate the left side of the equation.
$7(1) +3 =7 +3 =10$

STEP 4

Calculate the right side of the equation.
$6(1) - =6 - =1$

STEP 5

Compare the left and right sides of the equation. If they are equal, then $x =1$ is a solution. If they are not equal, then $x =1$ is not a solution.
Since $10 \neq1$ , $x =1$ is not a solution to the equation $7x +3 =x -5$ .
So, the answer is "No".

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QuestionCheck if 111 is a solution to the equation 7x+3=6x−57x + 3 = 6x - 57x+3=6x−5.

Studdy Solution

STEP 1

Assumptions1. The equation to be solved is 7x+3=6x−57x +3 =6x -57x+3=6x−5 . We are checking if x=1x =1x=1 is a solution to the equation

STEP 2

To check if x=1x =1x=1 is a solution, we substitute x=1x =1x=1 into the equation and see if both sides are equal.7(1)+=6(1)−57(1) + =6(1) -57(1)+=6(1)−5

STEP 3

Calculate the left side of the equation.7(1)+3=7+3=107(1) +3 =7 +3 =107(1)+3=7+3=10

STEP 4

Calculate the right side of the equation.6(1)−=6−=16(1) - =6 - =16(1)−=6−=1

STEP 5

Compare the left and right sides of the equation. If they are equal, then x=1x =1x=1 is a solution. If they are not equal, then x=1x =1x=1 is not a solution.Since 10≠110 \neq110=1, x=1x =1x=1 is not a solution to the equation 7x+3=x−57x +3 =x -57x+3=x−5.So, the answer is "No".

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QuestionCheck if $1$ is a solution to the equation $7x + 3 = 6x - 5$ .

Assumptions1. The equation to be solved is $7x +3 =6x -5$ . We are checking if $x =1$ is a solution to the equation

To check if $x =1$ is a solution, we substitute $x =1$ into the equation and see if both sides are equal.
$7(1) + =6(1) -5$

Calculate the left side of the equation.
$7(1) +3 =7 +3 =10$

Calculate the right side of the equation.
$6(1) - =6 - =1$

Compare the left and right sides of the equation. If they are equal, then $x =1$ is a solution. If they are not equal, then $x =1$ is not a solution.
Since $10 \neq1$ , $x =1$ is not a solution to the equation $7x +3 =x -5$ .
So, the answer is "No".