Math

QuestionFind the number of electrons, protons, and neutrons in the isotope 77192Ir^{192}_{77}\mathrm{Ir}.

Studdy Solution

STEP 1

Assumptions1. The given isotope is 77192Ir{ }_{77}^{192} \mathrm{Ir}. . The lower number (77) represents the atomic number (Z), which is the number of protons in the nucleus of an atom.
3. The upper number (192) represents the mass number (A), which is the total number of protons and neutrons in the nucleus.
4. The number of electrons in a neutral atom is equal to the number of protons.

STEP 2

We can find the number of protons in the isotope by looking at the atomic number (Z).
Protons=ZProtons = Z

STEP 3

Plug in the given atomic number to find the number of protons.
Protons=77Protons =77

STEP 4

We can find the number of neutrons in the isotope by subtracting the atomic number (Z) from the mass number (A).
Neutrons=AZNeutrons = A - Z

STEP 5

Plug in the given mass number and atomic number to find the number of neutrons.
Neutrons=19277Neutrons =192 -77

STEP 6

Calculate the number of neutrons.
Neutrons=19277=115Neutrons =192 -77 =115

STEP 7

We can find the number of electrons in a neutral atom by looking at the atomic number (Z), because the number of electrons is equal to the number of protons.
Electrons=ZElectrons = Z

STEP 8

Plug in the given atomic number to find the number of electrons.
Electrons=77Electrons =77In an atom of the isotope 77192Ir{ }_{77}^{192} \mathrm{Ir}, there are77 electrons,77 protons, and115 neutrons.

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