QuestionCalculate the increase in carbon dioxide from 325 ppm in 1959 to 373 ppm in 2005, and find the percent increase: $\%$ .

Studdy Solution

STEP 1

Assumptions1. The initial carbon dioxide level in1959 was325 parts per million (ppm). . The carbon dioxide level in2005 was373 ppm.
3. We are asked to find the increase in carbon dioxide levels and the percent of increase.

STEP 2

First, we need to find the increase in carbon dioxide levels. We can do this by subtracting the initial level from the final level.
$Increase = Final\, level - Initial\, level$

STEP 3

Now, plug in the given values for the initial and final levels to calculate the increase.
$Increase =373\, ppm -325\, ppm$

STEP 4

Calculate the increase in carbon dioxide levels.
$Increase =373\, ppm -325\, ppm =48\, ppm$

STEP 5

Now that we have the increase in carbon dioxide levels, we can find the percent of increase. This is done by dividing the increase by the initial level and then multiplying by100 to get a percentage.
$Percent\, increase = \left(\frac{Increase}{Initial\, level}\right) \times100\%$

STEP 6

Plug in the values for the increase and the initial level to calculate the percent increase.
$Percent\, increase = \left(\frac{48\, ppm}{325\, ppm}\right) \times100\%$

STEP 7

Calculate the percent increase.
$Percent\, increase = \left(\frac{48\, ppm}{325\, ppm}\right) \times100\% =14.76923076923077\%$

STEP 8

Round the percent increase to the nearest tenth of a percent.
$Percent\, increase =14.8\%$ The increase in carbon dioxide levels is48 ppm and the percent of increase is14.8%.

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