Math  /  Geometry

QuestionIn the figure below, m2=126m \angle 2=126^{\circ}. Find m1,m3m \angle 1, m \angle 3, and m4m \angle 4.

Studdy Solution

STEP 1

1. Vertically opposite angles are equal.
2. The sum of angles on a straight line is 180180^\circ.

STEP 2

1. Identify the relationship between angles.
2. Calculate m1m \angle 1.
3. Calculate m3m \angle 3.
4. Calculate m4m \angle 4.

STEP 3

Identify that angles 1 and 3 are vertically opposite, and angles 2 and 4 are vertically opposite. Therefore, m1=m3m \angle 1 = m \angle 3 and m2=m4m \angle 2 = m \angle 4.

STEP 4

Since angles 1 and 2 are on a straight line, their sum is 180180^\circ. Therefore, we have:
m1+m2=180 m \angle 1 + m \angle 2 = 180^\circ
Substitute m2=126m \angle 2 = 126^\circ:
m1+126=180 m \angle 1 + 126^\circ = 180^\circ

STEP 5

Solve for m1m \angle 1:
m1=180126 m \angle 1 = 180^\circ - 126^\circ m1=54 m \angle 1 = 54^\circ

STEP 6

Since m1=m3m \angle 1 = m \angle 3 (vertically opposite angles), we have:
m3=54 m \angle 3 = 54^\circ

STEP 7

Since m2=m4m \angle 2 = m \angle 4 (vertically opposite angles), we have:
m4=126 m \angle 4 = 126^\circ
The measures of the angles are: m1=54 m \angle 1 = 54^\circ m3=54 m \angle 3 = 54^\circ m4=126 m \angle 4 = 126^\circ

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