Math  /  Geometry

QuestionIn the diagram, lines \ell and mm are cut by transversals nn and ρ\rho.
Part A Enter the measure of 1\angle 1. \square
Part B Enter the measure of 2\angle 2. \square

Studdy Solution

STEP 1

What is this asking? We need to find the measure of two angles formed when two lines are crossed by two other lines, and we know one of the angles is 5959^\circ. Watch out! Don't mix up which angles are equal!
Remember the relationships between angles formed by intersecting lines.

STEP 2

1. Find Angle 1
2. Find Angle 2

STEP 3

Look closely!
Angle 1 and the 5959^\circ angle form a **straight line** together.
That means they're **supplementary angles**, and they add up to 180180^\circ!

STEP 4

So, to find the measure of Angle 1, we **subtract** 5959^\circ from 180180^\circ.
Let's do it: 18059=121180^\circ - 59^\circ = 121^\circ

STEP 5

Therefore, the measure of Angle 1 is **121121^\circ**.

STEP 6

Notice that Angle 2 and the 5959^\circ angle are **vertically opposite** each other.

STEP 7

Vertically opposite angles are **always equal**!

STEP 8

That means Angle 2 also measures **5959^\circ**.

STEP 9

Part A: The measure of 1\angle 1 is 121121^\circ. Part B: The measure of 2\angle 2 is 5959^\circ.

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