QuestionIn Bloomington, they randomly sampled 210 female voters, and 440 male voters. They collected data on the respondent's opinion on an environmental bond issue. We want to know whether there is good evidence that one's gender influences whether a person is for or against the bond issue. Use .
\begin{tabular}{|c|c|c|c|}
\hline & For Bond Issue & Against Bond Issue & Total \\
\hline Men & 51 & 159 & 210 \\
\hline Women & 39 & 401 & 440 \\
\hline Total & 90 & 560 & 650 \\
\hline
\end{tabular}
a) What is the correct null hypothesis?
: Gender and Bond Issue Attitudes are dependent.
: Gender and Bond Issue Attitudes are Independent.
b) Fill in the expected values, round answers to 1 decimal place.
\begin{tabular}{|c|c|c|}
\hline \begin{tabular}{c}
Expected \\
Values
\end{tabular} & For Bond Issue & \begin{tabular}{c}
Against \\
Bond Issue
\end{tabular} \\
\hline Men & & \\
\hline Women & & \\
\hline
\end{tabular}
c) Chi Square Test Statistic Round answer to 1 decimal place.
Degree's of Freedom
d) The -value Round answer to 3 decimal places.
Studdy Solution
STEP 1
1. We are conducting a chi-square test for independence.
2. The significance level is 0.1.
3. The null hypothesis is that gender and bond issue attitudes are independent.
STEP 2
1. Define the null hypothesis.
2. Calculate the expected values.
3. Compute the chi-square test statistic.
4. Determine the degrees of freedom.
5. Calculate the p-value.
STEP 3
Define the null hypothesis:
STEP 4
Calculate the expected values using the formula:
For Men, For Bond Issue:
For Men, Against Bond Issue:
For Women, For Bond Issue:
For Women, Against Bond Issue:
STEP 5
Compute the chi-square test statistic using the formula:
Where is the observed frequency and is the expected frequency.
For Men, For Bond Issue:
For Men, Against Bond Issue:
For Women, For Bond Issue:
For Women, Against Bond Issue:
Summing these values gives:
STEP 6
Determine the degrees of freedom using the formula:
STEP 7
Calculate the p-value using the chi-square distribution table or calculator for and 1 degree of freedom.
The p-value is approximately:
The solution is:
a) Null Hypothesis:
b) Expected Values:
c) Chi Square Test Statistic
Degrees of Freedom
d) The -value
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