Math  /  Geometry

Question(A)

Studdy Solution

STEP 1

What is this asking? We need to find the value of xx in a right triangle where the other two angles are xx^\circ and 2x2x^\circ. Watch out! Don't forget that the angles in a triangle always add up to 180180^\circ!

STEP 2

1. Set up the equation
2. Solve for *x*

STEP 3

Alright, so we've got a **right triangle**, which means one of the angles is 90\boldsymbol{90^\circ}!
We also know the other two angles are xx^\circ and 2x2x^\circ.

STEP 4

The **sum of angles** in *any* triangle is always 180\boldsymbol{180^\circ}.
This is a fundamental fact in geometry!
So, we can set up an equation: x+2x+90=180x + 2x + 90 = 180.
See how we just added up all three angles and set them equal to 180180?

STEP 5

Let's **simplify** the left side of our equation: x+2xx + 2x gives us 3x3x.
So, our equation becomes 3x+90=1803x + 90 = 180.

STEP 6

Now, we want to **isolate** x\boldsymbol{x}.
Let's subtract 9090 from both sides of the equation: 3x+9090=180903x + 90 - 90 = 180 - 90.
This simplifies to 3x=903x = 90.
We're getting closer!

STEP 7

Finally, we **divide** both sides by 33 to get xx all by itself: 3x3=903\frac{3x}{3} = \frac{90}{3}.
This gives us our **final answer**: x=30x = 30.
Boom!

STEP 8

The value of xx is 30\boldsymbol{30}.
So, the angles in our triangle are 3030^\circ, 230=602 \cdot 30^\circ = 60^\circ, and 9090^\circ.

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