Math

QuestionGiven yy varies inversely with xx and y=32y=-\frac{3}{2} when x=8x=-8, find the equation and yy when x=6x=6. y= y =

Studdy Solution

STEP 1

Assumptions1. yy varies inversely with xx. . y=3y=-\frac{3}{} when x=8x=-8.
3. The inverse variation equation is of the form y=kxy = \frac{k}{x}, where kk is the constant of variation.

STEP 2

First, we need to find the constant of variation kk. We can do this by rearranging the inverse variation equation and plugging in the given values for xx and yy.
k=y×xk = y \times x

STEP 3

Now, plug in the given values for xx and yy to calculate kk.
k=32×8k = -\frac{3}{2} \times -8

STEP 4

Calculate the constant of variation kk.
k=32×8=12k = -\frac{3}{2} \times -8 =12

STEP 5

Now that we have the constant of variation, we can write the inverse variation equation that relates xx and yy.
y=kxy = \frac{k}{x}

STEP 6

Plug in the value for kk to write the inverse variation equation.
y=12xy = \frac{12}{x}This is the inverse variation equation that relates xx and yy.

STEP 7

Now, we can use this equation to find yy when x=6x=6. Plug in the value for xx into the equation.
y=126y = \frac{12}{6}

STEP 8

Calculate the value of yy.
y=126=2y = \frac{12}{6} =2So, when x=6x=6, y=2y=2.

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