QuestionEvaluate $\frac{2 x-31}{y-5}$ for $x=-7$ and $y=-4$ . Is it a number or undefined?

Studdy Solution

STEP 1

Assumptions1. The value of $x$ is $-7$ . The value of $y$ is $-4$

STEP 2

We need to substitute the given values of $x$ and $y$ into the expression. $\frac{2 x-31}{y-5}$

STEP 3

Substitute $x = -7$ and $y = -$ into the expression.
$\frac{2(-7)-31}{--5}$

STEP 4

implify the numerator and denominator separately.
$\frac{-14-31}{-4-}$

STEP 5

Calculate the numerator and denominator.
$\frac{-45}{-9}$

STEP 6

Finally, divide the numerator by the denominator.
$\frac{-45}{-9} =5$ So, the correct choice is A. $\frac{2 x-31}{y-5}=5$

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QuestionEvaluate $\frac{2 x-31}{y-5}$ for $x=-7$ and $y=-4$ . Is it a number or undefined?

Studdy Solution

STEP 1

Assumptions1. The value of $x$ is $-7$ . The value of $y$ is $-4$

STEP 2

We need to substitute the given values of $x$ and $y$ into the expression. $\frac{2 x-31}{y-5}$

STEP 3

Substitute $x = -7$ and $y = -$ into the expression.
$\frac{2(-7)-31}{--5}$

STEP 4

implify the numerator and denominator separately.
$\frac{-14-31}{-4-}$

STEP 5

Calculate the numerator and denominator.
$\frac{-45}{-9}$

STEP 6

Finally, divide the numerator by the denominator.
$\frac{-45}{-9} =5$ So, the correct choice is A. $\frac{2 x-31}{y-5}=5$

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QuestionEvaluate 2x−31y−5\frac{2 x-31}{y-5}y−52x−31​ for x=−7x=-7x=−7 and y=−4y=-4y=−4. Is it a number or undefined?

Studdy Solution

STEP 1

Assumptions1. The value of xxx is −7-7−7 . The value of yyy is −4-4−4

STEP 2

We need to substitute the given values of xxx and yyy into the expression.2x−31y−5\frac{2 x-31}{y-5}y−52x−31​

STEP 3

Substitute x=−7x = -7x=−7 and y=−y = -y=− into the expression.2(−7)−31−−5\frac{2(-7)-31}{--5}−−52(−7)−31​

STEP 4

implify the numerator and denominator separately.−14−31−4−\frac{-14-31}{-4-}−4−−14−31​

STEP 5

Calculate the numerator and denominator.−45−9\frac{-45}{-9}−9−45​

STEP 6

Finally, divide the numerator by the denominator.−45−9=5\frac{-45}{-9} =5−9−45​=5So, the correct choice is A. 2x−31y−5=5\frac{2 x-31}{y-5}=5y−52x−31​=5

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QuestionEvaluate $\frac{2 x-31}{y-5}$ for $x=-7$ and $y=-4$ . Is it a number or undefined?

Assumptions1. The value of $x$ is $-7$ . The value of $y$ is $-4$

We need to substitute the given values of $x$ and $y$ into the expression. $\frac{2 x-31}{y-5}$

Substitute $x = -7$ and $y = -$ into the expression.
$\frac{2(-7)-31}{--5}$

implify the numerator and denominator separately.
$\frac{-14-31}{-4-}$

Calculate the numerator and denominator.
$\frac{-45}{-9}$

Finally, divide the numerator by the denominator.
$\frac{-45}{-9} =5$ So, the correct choice is A. $\frac{2 x-31}{y-5}=5$