Math

QuestionFind x5y+1x^{5} y + 1 if (x+2,y)=(2,3)(x+2, y) = (2, 3). Options: (a) 3 (b) 2 (c) 0 (d) 1.

Studdy Solution

STEP 1

Assumptions1. The given equation is (x+,y)=(,3)(x+, y)=(,3). We need to find the value of x5y+1x^{5} y+1

STEP 2

The given equation can be split into two equations. The first one is x+2=2x+2=2 and the second one is y=y=.

STEP 3

Let's solve the first equation for xx.
x+2=2x+2=2

STEP 4

Subtract2 from both sides of the equation to solve for xx.
x=22x =2 -2

STEP 5

Calculate the value of xx.
x=22=0x =2 -2 =0

STEP 6

Now that we have the value of xx, we can substitute x=0x=0 and y=3y=3 into the equation x5y+1x^{5} y+1 to find its value.
x5y+1=053+1x^{5} y+1 =0^{5} \cdot3 +1

STEP 7

Calculate the value of x5y+1x^{5} y+1.
x5y+1=03+1=0+1=1x^{5} y+1 =0 \cdot3 +1 =0 +1 =1So, x5y+1=1x^{5} y+1=1. Therefore, the correct answer is (d)1.

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