PROBLEM
If the null space of a 7×5 matrix is 4 -dimensional, find rank A, dimRowA, and dimColA.
A. rank A=1,dimRowA=4,dimColA=4
B. rank A=1,dimRowA=1,dimColA=4
C. rank A=3,dimRowA=3,dimColA=3
D. rankA=1,dimRowA=1,dimColA=1
STEP 1
1. The matrix A is a 7×5 matrix.
2. The null space of A is 4-dimensional.
3. The rank-nullity theorem applies, which states that for a matrix A with n columns, rank(A)+nullity(A)=n.
STEP 2
1. Use the rank-nullity theorem to find the rank of A.
2. Determine dimRowA.
3. Determine dimColA.
4. Compare results with the given options.
STEP 3
Apply the rank-nullity theorem. For a 7×5 matrix A, the number of columns n=5. The nullity of A is given as 4. Therefore, we can write:
rank(A)+nullity(A)=n rank(A)+4=5 Solve for rank(A):
rank(A)=5−4=1
STEP 4
The dimension of the row space of A is equal to the rank of A. Therefore:
dimRowA=rank(A)=1
STEP 5
The dimension of the column space of A is also equal to the rank of A. Therefore:
dimColA=rank(A)=1
SOLUTION
Compare the results with the given options:
- rank A=1
- dimRowA=1
- dimColA=1
The correct option is:
D. rankA=1,dimRowA=1,dimColA=1
The correct answer is:
D
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