Math  /  Algebra

QuestionIf s(x)=x7s(x)=x-7 and t(x)=4x2x+3t(x)=4 x^{2}-x+3, which expression is equivalent to (ts)(x)?(t \circ s)(x) ? 4(x7)2x7+34(x-7)^{2}-x-7+3 4(x7)2(x7)+34(x-7)^{2}-(x-7)+3 (4x2x+3)7\left(4 x^{2}-x+3\right)-7 (4x2x+3)(x7)\left(4 x^{2}-x+3\right)(x-7)

Studdy Solution

STEP 1

1. We are given two functions, s(x)=x7 s(x) = x - 7 and t(x)=4x2x+3 t(x) = 4x^2 - x + 3 .
2. We need to find the expression for the composition of functions (ts)(x) (t \circ s)(x) , which means t(s(x)) t(s(x)) .

STEP 2

1. Substitute s(x) s(x) into t(x) t(x) .
2. Simplify the resulting expression.

STEP 3

Substitute s(x)=x7 s(x) = x - 7 into t(x)=4x2x+3 t(x) = 4x^2 - x + 3 .
t(s(x))=t(x7)=4(x7)2(x7)+3 t(s(x)) = t(x - 7) = 4(x - 7)^2 - (x - 7) + 3

STEP 4

Simplify the expression 4(x7)2(x7)+3 4(x - 7)^2 - (x - 7) + 3 .
Notice that the expression is already in a simplified form that matches one of the given options.
The equivalent expression for (ts)(x) (t \circ s)(x) is:
4(x7)2(x7)+3 \boxed{4(x-7)^{2}-(x-7)+3}

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