QuestionProve that if $-\frac{1}{6} r - 5 = 38$ , then $r = -258$ using a two-column format.

Studdy Solution

STEP 1

Assumptions1. The given equation is $-\frac{1}{6} r-5=38$ . We need to prove that $r=-258$

STEP 2

The first step in a two-column proof is to write down the given equation, which is our hypothesis.
$-\frac{1}{6} r-5=38$

STEP 3

Next, we isolate $-\frac{1}{6} r$ on one side of the equation by adding $5$ to both sides.
$-\frac{1}{6} r =38 +5$

STEP 4

Calculate the right side of the equation.
$-\frac{1}{6} r =43$

STEP 5

To isolate $r$ , we multiply both sides of the equation by $-$ .
$r =43 \times -$

STEP 6

Calculate the right side of the equation.
$r = -258$ This is the conclusion of our proof.

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QuestionProve that if $-\frac{1}{6} r - 5 = 38$ , then $r = -258$ using a two-column format.

Studdy Solution

STEP 1

Assumptions1. The given equation is $-\frac{1}{6} r-5=38$ . We need to prove that $r=-258$

STEP 2

The first step in a two-column proof is to write down the given equation, which is our hypothesis.
$-\frac{1}{6} r-5=38$

STEP 3

Next, we isolate $-\frac{1}{6} r$ on one side of the equation by adding $5$ to both sides.
$-\frac{1}{6} r =38 +5$

STEP 4

Calculate the right side of the equation.
$-\frac{1}{6} r =43$

STEP 5

To isolate $r$ , we multiply both sides of the equation by $-$ .
$r =43 \times -$

STEP 6

Calculate the right side of the equation.
$r = -258$ This is the conclusion of our proof.

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QuestionProve that if −16r−5=38-\frac{1}{6} r - 5 = 38−61​r−5=38, then r=−258r = -258r=−258 using a two-column format.

Studdy Solution

STEP 1

Assumptions1. The given equation is −16r−5=38-\frac{1}{6} r-5=38−61​r−5=38 . We need to prove that r=−258r=-258r=−258

STEP 2

The first step in a two-column proof is to write down the given equation, which is our hypothesis.−16r−5=38-\frac{1}{6} r-5=38−61​r−5=38

STEP 3

Next, we isolate −16r-\frac{1}{6} r−61​r on one side of the equation by adding 555 to both sides.−16r=38+5-\frac{1}{6} r =38 +5−61​r=38+5

STEP 4

Calculate the right side of the equation.−16r=43-\frac{1}{6} r =43−61​r=43

STEP 5

To isolate rrr, we multiply both sides of the equation by −-−.r=43×−r =43 \times -r=43×−

STEP 6

Calculate the right side of the equation.r=−258r = -258r=−258This is the conclusion of our proof.

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Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

QuestionProve that if $-\frac{1}{6} r - 5 = 38$ , then $r = -258$ using a two-column format.

Assumptions1. The given equation is $-\frac{1}{6} r-5=38$ . We need to prove that $r=-258$

The first step in a two-column proof is to write down the given equation, which is our hypothesis.
$-\frac{1}{6} r-5=38$

Next, we isolate $-\frac{1}{6} r$ on one side of the equation by adding $5$ to both sides.
$-\frac{1}{6} r =38 +5$

Calculate the right side of the equation.
$-\frac{1}{6} r =43$

To isolate $r$ , we multiply both sides of the equation by $-$ .
$r =43 \times -$

Calculate the right side of the equation.
$r = -258$ This is the conclusion of our proof.