Math

QuestionFind the value not in the range of f(g(x))f(g(x)) where f(x)=52xf(x)=5-2x and g(x)=x24g(x)=\frac{x^{2}}{4}.

Studdy Solution

STEP 1

Assumptions1. The function f(x)f(x) is defined as f(x)=5xf(x) =5 -x . The function g(x)g(x) is defined as g(x)=x4g(x) = \frac{x^{}}{4}
3. We need to find the range of the composite function f(g(x))f(g(x))

STEP 2

First, we need to find the composite function f(g(x))f(g(x)). This is done by substituting g(x)g(x) into f(x)f(x).
f(g(x))=f(x24)f(g(x)) = f\left(\frac{x^{2}}{4}\right)

STEP 3

Substitute x2\frac{x^{2}}{} for xx in f(x)f(x) to get f(g(x))f(g(x)).
f(g(x))=52(x2)f(g(x)) =5 -2\left(\frac{x^{2}}{}\right)

STEP 4

implify the expression to get the composite function f(g(x))f(g(x)).
f(g(x))=x22f(g(x)) = - \frac{x^{2}}{2}

STEP 5

Now, we need to find the range of f(g(x))f(g(x)). The range of a function is the set of all possible output values (y-values), which are determined by the domain of the function.For the function f(g(x))=5x22f(g(x)) =5 - \frac{x^{2}}{2}, the domain is all real numbers because xx can be any real number.

STEP 6

The function f(g(x))=5x22f(g(x)) =5 - \frac{x^{2}}{2} is a downward-opening parabola with a vertex at (0,5)(0,5). This means that the maximum value of the function is5, and it can take on any value less than or equal to5.Therefore, the range of f(g(x))f(g(x)) is (,5](-\infty,5].

STEP 7

Any number greater than5 is not in the range of f(g(x))f(g(x)).

Was this helpful?

Studdy solves anything!

banner

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

ParentsInfluencer programContactPolicyTerms
TwitterInstagramFacebookTikTokDiscord