Math

QuestionAfter how many months will Bob's old internet (655065 - 50) equal the new provider's (150+40×150 + 40 \times months)?

Studdy Solution

STEP 1

Assumptions1. The old internet provider charges 65permonthandoffersa65 per month and offers a 50 customer loyalty credit. . The new internet provider charges a one-time installation fee of 150and150 and 40 per month.
3. We need to find the number of months after which the cost of both options will be equal.

STEP 2

First, we need to calculate the monthly cost for the old internet provider. This can be done by subtracting the customer loyalty credit from the monthly fee.
Oldprovidercost=MonthlyfeeCustomerloyaltycreditOld\, provider\, cost = Monthly\, fee - Customer\, loyalty\, credit

STEP 3

Now, plug in the given values for the monthly fee and customer loyalty credit to calculate the cost for the old provider.
Oldprovidercost=$65$50Old\, provider\, cost = \$65 - \$50

STEP 4

Calculate the monthly cost for the old internet provider.
Oldprovidercost=$65$50=$15Old\, provider\, cost = \$65 - \$50 = \$15

STEP 5

Now, we need to calculate the total cost for each provider after 'n' months. For the old provider, this is simply the monthly cost times the number of months.
Oldprovidertotalcost=OldprovidercosttimesnOld\, provider\, total\, cost = Old\, provider\, cost \\times n

STEP 6

For the new provider, the total cost includes the one-time installation fee plus the monthly fee times the number of months.
Newprovidertotalcost=Installationfee+(Monthlyfeetimesn)New\, provider\, total\, cost = Installation\, fee + (Monthly\, fee \\times n)

STEP 7

We need to find the number of months 'n' after which the total cost for both providers will be the same. This gives us the equationOldprovidertotalcost=NewprovidertotalcostOld\, provider\, total\, cost = New\, provider\, total\, cost

STEP 8

Substitute the expressions for the total cost of both providers into the equation.
Oldprovidercosttimesn=Installationfee+(Monthlyfeetimesn)Old\, provider\, cost \\times n = Installation\, fee + (Monthly\, fee \\times n)

STEP 9

Substitute the known values into the equation.
$15timesn=$150+($40timesn)\$15 \\times n = \$150 + (\$40 \\times n)

STEP 10

Rearrange the equation to isolate 'n' on one side.
$15n$40n=$150\$15n - \$40n = \$150

STEP 11

implify the equation.
$25n=$150-\$25n = \$150

STEP 12

olve for 'n'.
n=$150/$25n = \$150 / -\$25

STEP 13

Calculate the number of months.
n=$150/$25=6n = \$150 / -\$25 = -6Since the number of months cannot be negative, we take the absolute value of 'n'.
n=6=6n = | -6 | =6So, the two options would cost the same after6 months.

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