QuestionFind the expression for $B - 2C$ in standard form, given $B = -t - 1$ and $C = 3t - 2$ .

Studdy Solution

STEP 1

Assumptions1. The given expressions are $B=-t-1$ and $C=3t-$ . We need to find an expression for $B-C$ in standard form

STEP 2

First, we need to write down the expression we want to simplify.
$B-2C$

STEP 3

Now, substitute the given expressions for B and C into the expression.
$B-2C = (-t-1) -2(3t-2)$

STEP 4

istribute the -2 across the terms in the parentheses.
$B-2C = -t-1 -6t +4$

STEP 5

Combine like terms to simplify the expression.
$B-2C = -7t +3$ So, the expression $B-2C$ in standard form is $-7t +3$ .

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QuestionFind the expression for $B - 2C$ in standard form, given $B = -t - 1$ and $C = 3t - 2$ .

Studdy Solution

STEP 1

Assumptions1. The given expressions are $B=-t-1$ and $C=3t-$ . We need to find an expression for $B-C$ in standard form

STEP 2

First, we need to write down the expression we want to simplify.
$B-2C$

STEP 3

Now, substitute the given expressions for B and C into the expression.
$B-2C = (-t-1) -2(3t-2)$

STEP 4

istribute the -2 across the terms in the parentheses.
$B-2C = -t-1 -6t +4$

STEP 5

Combine like terms to simplify the expression.
$B-2C = -7t +3$ So, the expression $B-2C$ in standard form is $-7t +3$ .

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QuestionFind the expression for B−2CB - 2CB−2C in standard form, given B=−t−1B = -t - 1B=−t−1 and C=3t−2C = 3t - 2C=3t−2.

Studdy Solution

STEP 1

Assumptions1. The given expressions are B=−t−1B=-t-1B=−t−1 and C=3t−C=3t-C=3t− . We need to find an expression for B−CB-CB−C in standard form

STEP 2

First, we need to write down the expression we want to simplify.B−2CB-2CB−2C

STEP 3

Now, substitute the given expressions for B and C into the expression.B−2C=(−t−1)−2(3t−2)B-2C = (-t-1) -2(3t-2)B−2C=(−t−1)−2(3t−2)

STEP 4

istribute the -2 across the terms in the parentheses.B−2C=−t−1−6t+4B-2C = -t-1 -6t +4B−2C=−t−1−6t+4

STEP 5

Combine like terms to simplify the expression.B−2C=−7t+3B-2C = -7t +3B−2C=−7t+3So, the expression B−2CB-2CB−2C in standard form is −7t+3-7t +3−7t+3.

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QuestionFind the expression for $B - 2C$ in standard form, given $B = -t - 1$ and $C = 3t - 2$ .

Assumptions1. The given expressions are $B=-t-1$ and $C=3t-$ . We need to find an expression for $B-C$ in standard form

First, we need to write down the expression we want to simplify.
$B-2C$

Now, substitute the given expressions for B and C into the expression.
$B-2C = (-t-1) -2(3t-2)$

istribute the -2 across the terms in the parentheses.
$B-2C = -t-1 -6t +4$

Combine like terms to simplify the expression.
$B-2C = -7t +3$ So, the expression $B-2C$ in standard form is $-7t +3$ .