Math

QuestionIdentify the irrational numbers from the following: a. 53\sqrt{53}, b. 49\sqrt{49}, c. 256\sqrt{256}, d. 245\sqrt{245}, e. 2332-3 \sqrt{3}, f. 35\sqrt{3} \cdot 5. Choose all that apply.

Studdy Solution

STEP 1

Assumptions1. An irrational number is a number that cannot be expressed as a ratio of two integers. . The square root of a number is irrational if the number is not a perfect square.

STEP 2

We can determine if a number is irrational by taking its square root. If the square root is not a whole number, then the original number is irrational.

STEP 3

Calculate the square root of53.
53\sqrt{53}

STEP 4

Since53 is not a perfect square, its square root is not a whole number and therefore it is irrational.

STEP 5

Calculate the square root of49.
49\sqrt{49}

STEP 6

Since49 is a perfect square (^2), its square root is a whole number () and therefore it is not irrational.

STEP 7

Calculate the square root of256.
256\sqrt{256}

STEP 8

Since256 is a perfect square (16^2), its square root is a whole number (16) and therefore it is not irrational.

STEP 9

Calculate the square root of245.
245\sqrt{245}

STEP 10

Since245 is not a perfect square, its square root is not a whole number and therefore it is irrational.

STEP 11

For the expression 33-3 \sqrt{3}, we know that 3\sqrt{3} is irrational. Therefore, any operation involving an irrational number and a rational number (in this case, multiplication by -3 and addition of) will result in an irrational number.

STEP 12

For the expression 5\sqrt{} \cdot5, we know that \sqrt{} is irrational. Therefore, any operation involving an irrational number and a rational number (in this case, multiplication by5) will result in an irrational number.
The irrational numbers from the given options are 53\sqrt{53}, 245\sqrt{245}, 22- \sqrt{}, and 5\sqrt{} \cdot5. So, the correct options are B, D, F, and C.

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