QuestionIdentify the atom with four valence electrons that is shiny and has both metallic and nonmetallic properties: B, Sb, Sn, or Ge.
Studdy Solution
STEP 1
Assumptions1. The atom is shiny.
. The atom has the properties of both metals and nonmetals.
3. The atom has four valence electrons.
STEP 2
We need to identify the atom based on the given properties. The first property is that the atom is shiny. This property is common to metals, but not all metals have the properties of nonmetals. So, we need to look for an element that is a metalloid.
STEP 3
The second property is that the atom has the properties of both metals and nonmetals. This means the atom is a metalloid. Metalloids are elements that have properties of both metals and nonmetals. They are located along the staircase line on the periodic table.
STEP 4
The third property is that the atom has four valence electrons. Valence electrons are the electrons in the outermost shell of an atom that are involved in forming bonds with other atoms.
STEP 5
We can now look at the options given and eliminate the ones that do not meet all the properties.
STEP 6
Boron (B) is a metalloid, but it has three valence electrons, not four. So, Boron (B) is not the atom we are looking for.
STEP 7
Antimony (b) is a metalloid, but it has five valence electrons, not four. So, Antimony (b) is not the atom we are looking for.
STEP 8
in (Sn) is a metal, not a metalloid, and it has four valence electrons. But since it's not a metalloid, Tin (Sn) is not the atom we are looking for.
STEP 9
Germanium (Ge) is a metalloid and it has four valence electrons. So, Germanium (Ge) meets all the properties.
The atom being described here is Germanium (Ge).
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