Math

QuestionWhat happens to the equilibrium when H2\mathrm{H}_{2} gas is added to this reaction: 51.8 kJ+H2+I22HI51.8 \mathrm{~kJ}+\mathrm{H}_{2}+\mathrm{I}_{2} \rightleftharpoons 2 \mathrm{HI}?

Studdy Solution

STEP 1

Assumptions1. The system is initially at equilibrium. . H\mathrm{H}_{} gas is added to the system.
3. The system adjusts to reestablish equilibrium according to Le Chatelier's principle.

STEP 2

Le Chatelier's principle states that if a dynamic equilibrium is disturbed by changing the conditions, the position of equilibrium shifts to counteract the change. In this case, we have added extra H2\mathrm{H}_{2} gas to the system.

STEP 3

According to Le Chatelier's principle, the system will try to decrease the concentration of H2\mathrm{H}_{2} gas to reestablish equilibrium. This can be achieved by shifting the equilibrium to the right, towards the products, where H2\mathrm{H}_{2} is consumed.

STEP 4

When the equilibrium shifts to the right, the concentration of HI\mathrm{HI}, the product, will increase.

STEP 5

Therefore, the system adjusts to reestablish equilibrium by shifting the reaction to the right (products) and the concentration of HI\mathrm{HI} increases.
The correct answer is B. The reaction shifts to the right (products) and the concentration of HI\mathrm{HI} increases.

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