QuestionFind the number of protons $(p)$ and electrons $(e)$ in a $\mathrm{Se}^{2-}$ ion. Options: A) $34 p, 36 e$ B) $34 p, 32 e$ C) $32 p, 34 e$ D) $36 p, 34 e$ E) $34 p, 34 e$

Studdy Solution

STEP 1

Assumptions1. The ion under consideration is $\mathrm{Se}^{-}$ . . We are looking for the number of protons and electrons in this ion.
3. The atomic number of an element represents the number of protons in its nucleus.
4. The charge of an ion indicates the difference between the number of protons and electrons.

STEP 2

First, we need to find the atomic number of Selenium (Se). The atomic number of an element is equal to the number of protons in its nucleus.The atomic number of Selenium (Se) is34. So, it has34 protons.
$p =34$

STEP 3

Next, we need to find the number of electrons in the $\mathrm{Se}^{2-}$ ion.The charge of an ion is determined by the difference between the number of protons and electrons. A negative charge indicates that there are more electrons than protons.

STEP 4

Since the charge of the ion is $2-$ , this means there are2 more electrons than protons.We can express this relationship as $e = p + Charge$

STEP 5

Now, plug in the values for the number of protons and the charge to calculate the number of electrons.
$e =34 + (-2)$

STEP 6

Calculate the number of electrons.
$e =34 -2 =36$ So, the $\mathrm{Se}^{2-}$ ion has34 protons and36 electrons. Therefore, the answer is option A) $34 p,36 e$ .

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QuestionFind the number of protons $(p)$ and electrons $(e)$ in a $\mathrm{Se}^{2-}$ ion. Options: A) $34 p, 36 e$ B) $34 p, 32 e$ C) $32 p, 34 e$ D) $36 p, 34 e$ E) $34 p, 34 e$

Studdy Solution

STEP 1

STEP 2

First, we need to find the atomic number of Selenium (Se). The atomic number of an element is equal to the number of protons in its nucleus.The atomic number of Selenium (Se) is34. So, it has34 protons.
$p =34$

STEP 3

Next, we need to find the number of electrons in the $\mathrm{Se}^{2-}$ ion.The charge of an ion is determined by the difference between the number of protons and electrons. A negative charge indicates that there are more electrons than protons.

STEP 4

Since the charge of the ion is $2-$ , this means there are2 more electrons than protons.We can express this relationship as $e = p + Charge$

STEP 5

Now, plug in the values for the number of protons and the charge to calculate the number of electrons.
$e =34 + (-2)$

STEP 6

Calculate the number of electrons.
$e =34 -2 =36$ So, the $\mathrm{Se}^{2-}$ ion has34 protons and36 electrons. Therefore, the answer is option A) $34 p,36 e$ .

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QuestionFind the number of protons (p)(p)(p) and electrons (e)(e)(e) in a Se2−\mathrm{Se}^{2-}Se2− ion. Options: A) 34p,36e34 p, 36 e34p,36e B) 34p,32e34 p, 32 e34p,32e C) 32p,34e32 p, 34 e32p,34e D) 36p,34e36 p, 34 e36p,34e E) 34p,34e34 p, 34 e34p,34e

Studdy Solution

STEP 1

STEP 2

First, we need to find the atomic number of Selenium (Se). The atomic number of an element is equal to the number of protons in its nucleus.The atomic number of Selenium (Se) is34. So, it has34 protons.p=34p =34p=34

STEP 3

Next, we need to find the number of electrons in the Se2−\mathrm{Se}^{2-}Se2− ion.The charge of an ion is determined by the difference between the number of protons and electrons. A negative charge indicates that there are more electrons than protons.

STEP 4

Since the charge of the ion is 2−2-2−, this means there are2 more electrons than protons.We can express this relationship ase=p+Chargee = p + Chargee=p+Charge

STEP 5

Now, plug in the values for the number of protons and the charge to calculate the number of electrons.e=34+(−2)e =34 + (-2)e=34+(−2)

STEP 6

Calculate the number of electrons.e=34−2=36e =34 -2 =36e=34−2=36So, the Se2−\mathrm{Se}^{2-}Se2− ion has34 protons and36 electrons. Therefore, the answer is option A) 34p,36e34 p,36 e34p,36e.

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QuestionFind the number of protons $(p)$ and electrons $(e)$ in a $\mathrm{Se}^{2-}$ ion. Options: A) $34 p, 36 e$ B) $34 p, 32 e$ C) $32 p, 34 e$ D) $36 p, 34 e$ E) $34 p, 34 e$

First, we need to find the atomic number of Selenium (Se). The atomic number of an element is equal to the number of protons in its nucleus.The atomic number of Selenium (Se) is34. So, it has34 protons.
$p =34$

Next, we need to find the number of electrons in the $\mathrm{Se}^{2-}$ ion.The charge of an ion is determined by the difference between the number of protons and electrons. A negative charge indicates that there are more electrons than protons.

Since the charge of the ion is $2-$ , this means there are2 more electrons than protons.We can express this relationship as $e = p + Charge$

Now, plug in the values for the number of protons and the charge to calculate the number of electrons.
$e =34 + (-2)$

Calculate the number of electrons.
$e =34 -2 =36$ So, the $\mathrm{Se}^{2-}$ ion has34 protons and36 electrons. Therefore, the answer is option A) $34 p,36 e$ .