Math

QuestionDetermine the number of protons (p)(\mathrm{p}) and electrons (e)(\mathrm{e}) in a Sc3+\mathrm{Sc}^{3+} ion.

Studdy Solution

STEP 1

Assumptions1. The ion in question is Sc3+\mathrm{Sc}^{3+}. . The number of protons in an atom or ion is equal to its atomic number.
3. The number of electrons in a neutral atom is equal to its atomic number.
4. The number of electrons in an ion is equal to the atomic number minus the charge of the ion (since a positive charge indicates a loss of electrons).

STEP 2

First, we need to identify the atomic number of Scandium (Sc). The atomic number of an element can be found on the periodic table.
The atomic number of Scandium (Sc) is21.

STEP 3

The number of protons in an atom or ion is equal to its atomic number. Therefore, the number of protons in a Sc3+\mathrm{Sc}^{3+} ion is21.
Numberofprotons=Atomicnumber=21Number\, of\, protons = Atomic\, number =21

STEP 4

The number of electrons in an ion is equal to the atomic number minus the charge of the ion. Therefore, the number of electrons in a Sc3+\mathrm{Sc}^{3+} ion is21 -3 =18.
Numberofelectrons=AtomicnumberCharge=213=18Number\, of\, electrons = Atomic\, number - Charge =21 -3 =18The Sc3+\mathrm{Sc}^{3+} ion contains21 protons and18 electrons. Therefore, the correct answer is D) 21p,18e21 p,18 e.

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