QuestionHow many nanomoles (nmol) are in a 79.8 microgram ( $\mu \mathrm{g}$ ) sample of gold? Answer to 3 sig figs and in standard notation.

Studdy Solution

STEP 1

Assumptions1. The sample of gold is79.8 micrograms ( $\mu g$ ) . We are asked to find the amount in nanomoles (nmol)
3. The atomic weight of gold (Au) is approximately197.0 g/mol4. We will use the conversion factors1 g = $10^6$ $\mu g$ and1 mol = $10^9$ nmol

STEP 2

First, we need to convert the mass of the gold sample from micrograms to grams. We can do this by using the conversion factor1 g = $10^6$ $\mu g$ .
$Mass_{g} = Mass_{\mu g} /10^6$

STEP 3

Now, plug in the given value for the mass in micrograms to calculate the mass in grams.
$Mass_{g} =79.8 \mu g /10^6$

STEP 4

Calculate the mass in grams.
$Mass_{g} =79.8 \mu g /10^6 =7.98 \times10^{-} g$

STEP 5

Now that we have the mass in grams, we can find the number of moles by dividing the mass by the atomic weight of gold.
$Moles = Mass_{g} / Atomic\, weight$

STEP 6

Plug in the values for the mass in grams and the atomic weight of gold to calculate the number of moles.
$Moles =.98 \times10^{-5} g /197.0 g/mol$

STEP 7

Calculate the number of moles.
$Moles =7.98 \times10^{-5} g /197.0 g/mol =4.05 \times10^{-7} mol$

STEP 8

Now that we have the number of moles, we can convert this to nanomoles by using the conversion factor1 mol = 10^ nmol.
anomoles = Moles \times10^

STEP 9

Plug in the value for the number of moles to calculate the number of nanomoles.
$anomoles =4.05 \times^{-7} mol \times^9$

STEP 10

Calculate the number of nanomoles.
$anomoles =4.05 \times10^{-7} mol \times10^9 =405 nmol$ The79.8 microgram sample of gold is405 nmol.

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QuestionHow many nanomoles (nmol) are in a 79.8 microgram ( $\mu \mathrm{g}$ ) sample of gold? Answer to 3 sig figs and in standard notation.

Studdy Solution

STEP 1

Assumptions1. The sample of gold is79.8 micrograms ( $\mu g$ ) . We are asked to find the amount in nanomoles (nmol)
3. The atomic weight of gold (Au) is approximately197.0 g/mol4. We will use the conversion factors1 g = $10^6$ $\mu g$ and1 mol = $10^9$ nmol

STEP 2

First, we need to convert the mass of the gold sample from micrograms to grams. We can do this by using the conversion factor1 g = $10^6$ $\mu g$ .
$Mass_{g} = Mass_{\mu g} /10^6$

STEP 3

Now, plug in the given value for the mass in micrograms to calculate the mass in grams.
$Mass_{g} =79.8 \mu g /10^6$

STEP 4

Calculate the mass in grams.
$Mass_{g} =79.8 \mu g /10^6 =7.98 \times10^{-} g$

STEP 5

Now that we have the mass in grams, we can find the number of moles by dividing the mass by the atomic weight of gold.
$Moles = Mass_{g} / Atomic\, weight$

STEP 6

Plug in the values for the mass in grams and the atomic weight of gold to calculate the number of moles.
$Moles =.98 \times10^{-5} g /197.0 g/mol$

STEP 7

Calculate the number of moles.
$Moles =7.98 \times10^{-5} g /197.0 g/mol =4.05 \times10^{-7} mol$

STEP 8

Now that we have the number of moles, we can convert this to nanomoles by using the conversion factor1 mol = 10^ nmol.
anomoles = Moles \times10^

STEP 9

Plug in the value for the number of moles to calculate the number of nanomoles.
$anomoles =4.05 \times^{-7} mol \times^9$

STEP 10

Calculate the number of nanomoles.
$anomoles =4.05 \times10^{-7} mol \times10^9 =405 nmol$ The79.8 microgram sample of gold is405 nmol.

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QuestionHow many nanomoles (nmol) are in a 79.8 microgram (μg\mu \mathrm{g}μg) sample of gold? Answer to 3 sig figs and in standard notation.

Studdy Solution

STEP 1

Assumptions1. The sample of gold is79.8 micrograms (μg\mu gμg) . We are asked to find the amount in nanomoles (nmol)3. The atomic weight of gold (Au) is approximately197.0 g/mol4. We will use the conversion factors1 g = 10610^6106 μg\mu gμg and1 mol = 10910^9109 nmol

STEP 2

First, we need to convert the mass of the gold sample from micrograms to grams. We can do this by using the conversion factor1 g = 10610^6106 μg\mu gμg.Massg=Massμg/106Mass_{g} = Mass_{\mu g} /10^6Massg​=Massμg​/106

STEP 3

Now, plug in the given value for the mass in micrograms to calculate the mass in grams.Massg=79.8μg/106Mass_{g} =79.8 \mu g /10^6Massg​=79.8μg/106

STEP 4

Calculate the mass in grams.Massg=79.8μg/106=7.98×10−gMass_{g} =79.8 \mu g /10^6 =7.98 \times10^{-} gMassg​=79.8μg/106=7.98×10−g

STEP 5

Now that we have the mass in grams, we can find the number of moles by dividing the mass by the atomic weight of gold.Moles=Massg/Atomic weightMoles = Mass_{g} / Atomic\, weightMoles=Massg​/Atomicweight

STEP 6

Plug in the values for the mass in grams and the atomic weight of gold to calculate the number of moles.Moles=.98×10−5g/197.0g/molMoles =.98 \times10^{-5} g /197.0 g/molMoles=.98×10−5g/197.0g/mol

STEP 7

Calculate the number of moles.Moles=7.98×10−5g/197.0g/mol=4.05×10−7molMoles =7.98 \times10^{-5} g /197.0 g/mol =4.05 \times10^{-7} molMoles=7.98×10−5g/197.0g/mol=4.05×10−7mol

STEP 8

Now that we have the number of moles, we can convert this to nanomoles by using the conversion factor1 mol = 10^ nmol.anomoles = Moles \times10^

STEP 9

Plug in the value for the number of moles to calculate the number of nanomoles.anomoles=4.05×−7mol×9anomoles =4.05 \times^{-7} mol \times^9anomoles=4.05×−7mol×9

STEP 10

Calculate the number of nanomoles.anomoles=4.05×10−7mol×109=405nmolanomoles =4.05 \times10^{-7} mol \times10^9 =405 nmolanomoles=4.05×10−7mol×109=405nmolThe79.8 microgram sample of gold is405 nmol.

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QuestionHow many nanomoles (nmol) are in a 79.8 microgram ( $\mu \mathrm{g}$ ) sample of gold? Answer to 3 sig figs and in standard notation.

Assumptions1. The sample of gold is79.8 micrograms ( $\mu g$ ) . We are asked to find the amount in nanomoles (nmol)
3. The atomic weight of gold (Au) is approximately197.0 g/mol4. We will use the conversion factors1 g = $10^6$ $\mu g$ and1 mol = $10^9$ nmol

First, we need to convert the mass of the gold sample from micrograms to grams. We can do this by using the conversion factor1 g = $10^6$ $\mu g$ .
$Mass_{g} = Mass_{\mu g} /10^6$

Now, plug in the given value for the mass in micrograms to calculate the mass in grams.
$Mass_{g} =79.8 \mu g /10^6$

Calculate the mass in grams.
$Mass_{g} =79.8 \mu g /10^6 =7.98 \times10^{-} g$

Now that we have the mass in grams, we can find the number of moles by dividing the mass by the atomic weight of gold.
$Moles = Mass_{g} / Atomic\, weight$

Plug in the values for the mass in grams and the atomic weight of gold to calculate the number of moles.
$Moles =.98 \times10^{-5} g /197.0 g/mol$

Calculate the number of moles.
$Moles =7.98 \times10^{-5} g /197.0 g/mol =4.05 \times10^{-7} mol$

Now that we have the number of moles, we can convert this to nanomoles by using the conversion factor1 mol = 10^ nmol.
anomoles = Moles \times10^

Plug in the value for the number of moles to calculate the number of nanomoles.
$anomoles =4.05 \times^{-7} mol \times^9$

Calculate the number of nanomoles.
$anomoles =4.05 \times10^{-7} mol \times10^9 =405 nmol$ The79.8 microgram sample of gold is405 nmol.