Math  /  Algebra

QuestionHow does the graph of the transformation shown below compare to the graph of the parent function? g(x)=x42g(x)=-x^{4}-2
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The parent function is y=y= \square The leading coefficient of \square \square \square subtracting shifts the graph down 7 shifts the graph down \square unit! \square and (Type integers or decimals.) Help me solve this

Studdy Solution

STEP 1

What is this asking? How does flipping x4x^4 upside down and moving it down two units change its graph? Watch out! Don't mix up the negative in front of the x4x^4 and the 2-2.
They do totally different things!

STEP 2

1. Identify the parent function.
2. Analyze the negative coefficient.
3. Analyze the vertical shift.

STEP 3

The **parent function** is the simplest form of the given function type.
Here, our transformed function g(x)g(x) involves a variable raised to the fourth power.

STEP 4

So, the parent function is f(x)=x4f(x) = x^4.
It's like the starting point before any changes are made!

STEP 5

Now, let's look at that negative sign in front of the x4x^4 in g(x)=x42g(x) = -x^4 - 2.
This negative sign **flips** the graph of x4x^4 over the x-axis.

STEP 6

Imagine the parent function x4x^4 looking like a U.
The negative sign turns it upside down, like a hill or a frown!

STEP 7

Finally, we have that 2-2 hanging out at the end of g(x)=x42g(x) = -x^4 - 2.
This 2-2 causes a **vertical shift**.

STEP 8

Since it's 2-2, the graph of x4-x^4 is shifted **down** by **two** units.
Every point on the flipped parabola moves down two spots!

STEP 9

The parent function is y=x4y = x^4.
The leading coefficient of 1-1 flips the graph over the x-axis, and subtracting 22 shifts the graph down 22 units!

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