Math  /  Geometry

QuestionGraph the line with slope 12\frac{1}{2} passing through the point (4,3)(-4,3)

Studdy Solution

STEP 1

What is this asking? We need to draw a line on a graph that goes through the point (4,3)(-4,3) and has a slope of 12 \frac{1}{2} . Watch out! Remember slope is *rise over run*, and don't mix up your *x* and *y* coordinates!

STEP 2

1. Use the point-slope form
2. Convert to slope-intercept form
3. Identify the y-intercept
4. Plot the given point and the y-intercept
5. Draw the line

STEP 3

The point-slope form of a linear equation is given by yy1=m(xx1)y - y_1 = m(x - x_1), where mm is the **slope** and (x1,y1)(x_1, y_1) is a **given point** on the line.
This form is super useful because it lets us build the equation of a line if we know its slope and a point it passes through.

STEP 4

Our **slope** is m=12 m = \frac{1}{2} and our **given point** is (4,3)(-4, 3), so x1=4x_1 = -4 and y1=3y_1 = 3.
Let's plug these values into the point-slope form: y3=12(x(4))y - 3 = \frac{1}{2}(x - (-4)).

STEP 5

We can simplify this to y3=12(x+4)y - 3 = \frac{1}{2}(x + 4).
See how subtracting a negative number turns into addition?
Sneaky, right?

STEP 6

Let's distribute the 12\frac{1}{2} to both terms inside the parentheses: y3=12x+124y - 3 = \frac{1}{2} \cdot x + \frac{1}{2} \cdot 4, which simplifies to y3=12x+2y - 3 = \frac{1}{2}x + 2.

STEP 7

To get the slope-intercept form, we need to isolate yy.
We can do this by adding 33 to both sides of the equation: y3+3=12x+2+3y - 3 + 3 = \frac{1}{2}x + 2 + 3.
This simplifies to y=12x+5y = \frac{1}{2}x + 5.

STEP 8

Now our equation is in slope-intercept form, which is y=mx+by = mx + b, where mm is the **slope** and bb is the **y-intercept**.

STEP 9

In our equation, y=12x+5y = \frac{1}{2}x + 5, the **y-intercept** is 55, which means the line crosses the y-axis at the point (0,5)(0, 5).

STEP 10

First, plot the given point (4,3)(-4, 3).
Remember, the first number in the coordinate pair is the *x*-value, and the second is the *y*-value.

STEP 11

Next, plot the y-intercept, which is at (0,5)(0, 5).

STEP 12

Now, draw a straight line that passes through both points, (4,3)(-4, 3) and (0,5)(0, 5).
Extend the line beyond the points in both directions to show that it continues infinitely.

STEP 13

The graph of the line with slope 12 \frac{1}{2} passing through the point (4,3)(-4,3) is the line represented by the equation y=12x+5y = \frac{1}{2}x + 5, plotted through the points (4,3)(-4, 3) and (0,5)(0, 5) and extending infinitely in both directions.

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