QuestionGraph the line with slope $\frac{2}{5}$ and $y$ -intercept -5.

Studdy Solution

STEP 1

Assumptions1. The slope of the line is $\frac{}{5}$ . The y-intercept of the line is -53. The line is a straight line

STEP 2

The equation of a line in slope-intercept form is given by $y = mx + b$ where $m$ is the slope of the line and $b$ is the y-intercept.

STEP 3

Substitute the given values for the slope and y-intercept into the equation.
$y = \frac{2}{5}x -5$

STEP 4

To graph the line, start by plotting the y-intercept on the y-axis. The y-intercept is the point where the line crosses the y-axis. In this case, the y-intercept is -, so plot a point at (0, -).

STEP 5

From the y-intercept, use the slope to find another point on the line. The slope is the ratio of the vertical change (rise) to the horizontal change (run). In this case, the slope is $\frac{2}{5}$ , which means for every5 units you move to the right (positive direction on the x-axis), you move2 units up (positive direction on the y-axis).

STEP 6

Starting from the y-intercept (0, -5), move5 units to the right and2 units up to find another point on the line. This point is (5, -3).

STEP 7

Plot the point (5, -3) on the graph.

STEP 8

Draw a straight line through the points (0, -5) and (5, -3). This is the graph of the line with a slope of $\frac{2}{5}$ and a y-intercept of -5.

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QuestionGraph the line with slope $\frac{2}{5}$ and $y$ -intercept -5.

Studdy Solution

STEP 1

Assumptions1. The slope of the line is $\frac{}{5}$ . The y-intercept of the line is -53. The line is a straight line

STEP 2

The equation of a line in slope-intercept form is given by $y = mx + b$ where $m$ is the slope of the line and $b$ is the y-intercept.

STEP 3

Substitute the given values for the slope and y-intercept into the equation.
$y = \frac{2}{5}x -5$

STEP 4

To graph the line, start by plotting the y-intercept on the y-axis. The y-intercept is the point where the line crosses the y-axis. In this case, the y-intercept is -, so plot a point at (0, -).

STEP 5

STEP 6

Starting from the y-intercept (0, -5), move5 units to the right and2 units up to find another point on the line. This point is (5, -3).

STEP 7

Plot the point (5, -3) on the graph.

STEP 8

Draw a straight line through the points (0, -5) and (5, -3). This is the graph of the line with a slope of $\frac{2}{5}$ and a y-intercept of -5.

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QuestionGraph the line with slope 25\frac{2}{5}52​ and yyy-intercept -5.

Studdy Solution

STEP 1

Assumptions1. The slope of the line is 5\frac{}{5}5​ . The y-intercept of the line is -53. The line is a straight line

STEP 2

The equation of a line in slope-intercept form is given byy=mx+by = mx + by=mx+bwhere mmm is the slope of the line and bbb is the y-intercept.

STEP 3

Substitute the given values for the slope and y-intercept into the equation.y=25x−5y = \frac{2}{5}x -5y=52​x−5

STEP 4

To graph the line, start by plotting the y-intercept on the y-axis. The y-intercept is the point where the line crosses the y-axis. In this case, the y-intercept is -, so plot a point at (0, -).

STEP 5

STEP 6

Starting from the y-intercept (0, -5), move5 units to the right and2 units up to find another point on the line. This point is (5, -3).

STEP 7

Plot the point (5, -3) on the graph.

STEP 8

Draw a straight line through the points (0, -5) and (5, -3). This is the graph of the line with a slope of 25\frac{2}{5}52​ and a y-intercept of -5.

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QuestionGraph the line with slope $\frac{2}{5}$ and $y$ -intercept -5.

Assumptions1. The slope of the line is $\frac{}{5}$ . The y-intercept of the line is -53. The line is a straight line

The equation of a line in slope-intercept form is given by $y = mx + b$ where $m$ is the slope of the line and $b$ is the y-intercept.

Substitute the given values for the slope and y-intercept into the equation.
$y = \frac{2}{5}x -5$

Draw a straight line through the points (0, -5) and (5, -3). This is the graph of the line with a slope of $\frac{2}{5}$ and a y-intercept of -5.