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QuestionGrams A MMA\mathbf{M M}_{\mathrm{A}} Moles A mole ratio Moles B MMB\mathrm{MM}_{\mathrm{B}} Grams
What steps would you use to solve the following problem? Hydrogen and oxygen react to produce water as shown in the reaction below. 2H2( g)+O2( g)→2H2O( g)2 \mathrm{H}_{2}(\mathrm{~g})+\mathrm{O}_{2}(\mathrm{~g}) \rightarrow 2 \mathrm{H}_{2} \mathrm{O}(\mathrm{~g})
How many moles of water would be produced if 50.00 grams cf hydrogen reacted with excess oxygen gas? a. Step 1: Convert grams of hydrogen to moles of hydrogen with the molar mass of hydrogen.
Step 2: Convert moles of hydrogen to moles of water using the mole ratio from the balanced equation. Step 3: Convert moles of water to grams of water using the molar mass of water. b. Step 1: Convert grams of hydrogen to moles of hydrogen with the molar mass of hydrogen.
Step 2: Convert moles of hydrogen to moles of water using the mole ratio from the balanced equation. Step 3: Do not do this step. Problem is already done with correct units. c. Step 1: Skip this step and go directly to step 2.
Step 2: Convert moles of hydrogen to moles of water using the mole ratio from the balanced equation. Step 3: Convert moles of water to grams of water using the molar mass of water.
How many grams of oxygen will react with excess hydrogen to produce 25.0 grams of water in the synthesis of water reaction

Studdy Solution

STEP 1

1. The balanced chemical equation for the reaction is given.
2. We need to find the grams of oxygen required to produce 25.0 grams of water.
3. The reaction involves converting between grams and moles using molar masses and mole ratios.

STEP 2

1. Convert grams of water to moles of water.
2. Use the mole ratio to find moles of oxygen.
3. Convert moles of oxygen to grams of oxygen.

STEP 3

Convert grams of water to moles of water using the molar mass of water.
The molar mass of water (H2O\mathrm{H}_2\mathrm{O}) is approximately 18.02 g/mol18.02 \, \text{g/mol}.
Calculate moles of water: Moles of water=25.0 g18.02 g/mol\text{Moles of water} = \frac{25.0 \, \text{g}}{18.02 \, \text{g/mol}}

STEP 4

Use the balanced equation to find the mole ratio between water and oxygen.
From the balanced equation: 2H2( g)+O2( g)→2H2O( g) 2 \mathrm{H}_2(\mathrm{~g}) + \mathrm{O}_2(\mathrm{~g}) \rightarrow 2 \mathrm{H}_2\mathrm{O}(\mathrm{~g})
The mole ratio of H2O\mathrm{H}_2\mathrm{O} to O2\mathrm{O}_2 is 2:12:1.
Calculate moles of oxygen: Moles of oxygen=Moles of water2\text{Moles of oxygen} = \frac{\text{Moles of water}}{2}

STEP 5

Convert moles of oxygen to grams of oxygen using the molar mass of oxygen.
The molar mass of oxygen (O2\mathrm{O}_2) is approximately 32.00 g/mol32.00 \, \text{g/mol}.
Calculate grams of oxygen: Grams of oxygen=Moles of oxygen×32.00 g/mol\text{Grams of oxygen} = \text{Moles of oxygen} \times 32.00 \, \text{g/mol}
The solution provides the grams of oxygen needed to react with excess hydrogen to produce 25.0 grams of water.

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