Math  /  Geometry

QuestionGiven two points A(8,2)A(8,2) and B(1,4)B(-1,-4), the line segment ABA B cuts the xx-axis at P(x,0)P(x, 0), find the value of xx.

Studdy Solution

STEP 1

What is this asking? We need to find where the line connecting two points crosses the horizontal axis. Watch out! Don't mix up the xx and yy coordinates!
Also, remember that the yy-coordinate is **zero** where a line crosses the horizontal axis.

STEP 2

1. Find the slope
2. Find the equation of the line
3. Find the x-intercept

STEP 3

Let's **start** by finding the slope of the line segment ABAB.
Remember, the slope is the *rise over run*, or how much the yy-value changes for every change in the xx-value.

STEP 4

The slope formula is m=y2y1x2x1 m = \frac{y_2 - y_1}{x_2 - x_1} .
Let's plug in our points A(8,2)A(8, 2) and B(1,4)B(-1, -4).
We'll call (8,2)(8, 2) point 1, so x1=8x_1 = 8 and y1=2y_1 = 2.
Then (1,4)(-1, -4) is point 2, so x2=1x_2 = -1 and y2=4y_2 = -4.

STEP 5

Plugging those values into our formula gives us m=4218=69 m = \frac{-4 - 2}{-1 - 8} = \frac{-6}{-9} .
Now, we can simplify by dividing both the numerator and the denominator by 3-3, which is like multiplying by one in the form of 33\frac{-3}{-3}.
This gives us m=6933=23 m = \frac{-6}{-9} \cdot \frac{-3}{-3} = \frac{2}{3} .
So, our **slope** is 23 \frac{2}{3} .

STEP 6

Great! Now we have the slope.
We can use the point-slope form of a line, which is yy1=m(xx1) y - y_1 = m(x - x_1) .
Let's use point A(8,2)A(8, 2) and our slope m=23 m = \frac{2}{3} .

STEP 7

Substituting, we get y2=23(x8) y - 2 = \frac{2}{3}(x - 8) .
Let's distribute that 23\frac{2}{3} to get y2=23x163 y - 2 = \frac{2}{3}x - \frac{16}{3} .

STEP 8

Now, let's add 22 to both sides to isolate yy.
Remember, we can write 22 as 63\frac{6}{3} so that we have a common denominator.
This gives us y=23x163+63 y = \frac{2}{3}x - \frac{16}{3} + \frac{6}{3} , which simplifies to y=23x103 y = \frac{2}{3}x - \frac{10}{3} .
This is the **equation of our line**!

STEP 9

The xx-intercept is where the line crosses the xx-axis, which means the yy-coordinate is **zero**.
So, we can substitute y=0 y = 0 into our equation: 0=23x103 0 = \frac{2}{3}x - \frac{10}{3} .

STEP 10

Now, let's add 103\frac{10}{3} to both sides to get 103=23x \frac{10}{3} = \frac{2}{3}x .

STEP 11

To solve for xx, we can multiply both sides by 32\frac{3}{2}.
This is like multiplying by one in the form of 3/23/2\frac{3/2}{3/2}, which isolates xx.
We get 32103=3223x \frac{3}{2} \cdot \frac{10}{3} = \frac{3}{2} \cdot \frac{2}{3}x .

STEP 12

Simplifying gives us 306=x \frac{30}{6} = x , which reduces to x=5 x = 5 .
So, the **xx-intercept** is 55!

STEP 13

The line segment ABAB intersects the xx-axis at the point P(5,0)P(5, 0).

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