Math

QuestionCheck if f(x)=2x+10f(x) = -2x + 10 and g(x)=x102g(x) = \frac{x - 10}{-2} are inverses by finding (fg)(x)(f \circ g)(x) and (gf)(x)(g \circ f)(x).

Studdy Solution

STEP 1

Assumptions1. The function f(x)f(x) is defined as f(x)=x+10f(x)=-x+10 . The function g(x)g(x) is defined as g(x)=x10g(x)=\frac{x-10}{-}
3. We are asked to find the compositions (fg)(x)(f \circ g)(x) and (gf)(x)(g \circ f)(x)4. We are asked to determine if f(x)f(x) and g(x)g(x) are inverse functions. Two functions are inverses of each other if and only if both (fg)(x)=x(f \circ g)(x) = x and (gf)(x)=x(g \circ f)(x) = x.

STEP 2

First, we need to find the composition (fg)(x)(f \circ g)(x). This is done by substituting g(x)g(x) into f(x)f(x).
(fg)(x)=f(g(x))(f \circ g)(x) = f(g(x))

STEP 3

Substitute g(x)g(x) into f(x)f(x).
(fg)(x)=f(x102)(f \circ g)(x) = f\left(\frac{x-10}{-2}\right)

STEP 4

Now, replace xx in f(x)f(x) with x102\frac{x-10}{-2}.
(fg)(x)=2(x102)+10(f \circ g)(x) = -2\left(\frac{x-10}{-2}\right) +10

STEP 5

implify the expression.
(fg)(x)=x10+10(f \circ g)(x) = x -10 +10

STEP 6

Further simplify the expression.
(fg)(x)=x(f \circ g)(x) = x

STEP 7

Now, we need to find the composition (gf)(x)(g \circ f)(x). This is done by substituting f(x)f(x) into g(x)g(x).
(gf)(x)=g(f(x))(g \circ f)(x) = g(f(x))

STEP 8

Substitute f(x)f(x) into g(x)g(x).
(gf)(x)=g(2x+10)(g \circ f)(x) = g(-2x+10)

STEP 9

Now, replace xx in g(x)g(x) with 2x+-2x+.
(gf)(x)=2x+2(g \circ f)(x) = \frac{-2x+-}{-2}

STEP 10

implify the expression.
(gf)(x)=2x2(g \circ f)(x) = \frac{-2x}{-2}

STEP 11

Further simplify the expression.
(gf)(x)=x(g \circ f)(x) = x

STEP 12

Now that we have both (fg)(x)=x(f \circ g)(x) = x and (gf)(x)=x(g \circ f)(x) = x, we can conclude that f(x)f(x) and g(x)g(x) are inverse functions.
Thus, g(x)g(x) is the inverse function of f(x)f(x).

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