Math

QuestionFind the minimum value of the function f(x)=x26x+14f(x) = x^{2} - 6x + 14. Options: A) -3, B) 3, C) 5, D) 14.

Studdy Solution

STEP 1

Assumptions1. The function is f(x)=x6x+14f(x)=x^{}-6 x+14 . We need to find the minimum value of the function f(x)f(x)

STEP 2

The function f(x)=x26x+14f(x)=x^{2}-6 x+14 is a quadratic function. The general form of a quadratic function is f(x)=ax2+bx+cf(x)=ax^{2}+bx+c, where aa, bb, and cc are constants.The minimum or maximum value of a quadratic function occurs at x=b2ax=-\frac{b}{2a}.

STEP 3

In our function f(x)=x26x+14f(x)=x^{2}-6 x+14, we can identify a=1a=1, b=6b=-6, and c=14c=14.

STEP 4

Substitute a=1a=1 and b=6b=-6 into the formula x=b2ax=-\frac{b}{2a} to find the xx value at which the minimum occurs.
x=62(1)x=-\frac{-6}{2(1)}

STEP 5

Calculate the xx value.
x=2(1)=3x=-\frac{-}{2(1)} =3

STEP 6

Now that we have the xx value, we can substitute this into the function f(x)f(x) to find the minimum value.
f(3)=326(3)+14f(3)=3^{2}-6(3)+14

STEP 7

Calculate the value of f(3)f(3).
f(3)=326(3)+14=918+14=5f(3)=3^{2}-6(3)+14 =9 -18 +14 =5The minimum value of the function f(x)=x26x+14f(x)=x^{2}-6 x+14 is5.

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