Math  /  Algebra

QuestionFor each equation, choose the statement that describes its solution If applicable, give the solution. 2(y+1)+5y=3(y+1)2-2(y+1)+5 y=3(y+1)-2 No solution y=y= \square All real numbers are solutions 4(w+2)w=2(w1)+94(w+2)-w=2(w-1)+9 No solution w=w= \square All real numbers are solutions Check

Studdy Solution

STEP 1

1. We are given two separate equations to solve.
2. We need to determine if each equation has no solution, a specific solution, or if all real numbers are solutions.

STEP 2

1. Solve the first equation for y y .
2. Analyze the solution for the first equation.
3. Solve the second equation for w w .
4. Analyze the solution for the second equation.

STEP 3

Start with the first equation: 2(y+1)+5y=3(y+1)2 -2(y+1) + 5y = 3(y+1) - 2
Distribute the terms: 2y2+5y=3y+32 -2y - 2 + 5y = 3y + 3 - 2
Combine like terms: 3y2=3y+1 3y - 2 = 3y + 1

STEP 4

Subtract 3y 3y from both sides: 3y23y=3y+13y 3y - 2 - 3y = 3y + 1 - 3y
Simplify: 2=1 -2 = 1
This is a contradiction, which means there is no solution.

STEP 5

The first equation has no solution.

STEP 6

Start with the second equation: 4(w+2)w=2(w1)+9 4(w+2) - w = 2(w-1) + 9
Distribute the terms: 4w+8w=2w2+9 4w + 8 - w = 2w - 2 + 9
Combine like terms: 3w+8=2w+7 3w + 8 = 2w + 7

STEP 7

Subtract 2w 2w from both sides: 3w2w+8=2w2w+7 3w - 2w + 8 = 2w - 2w + 7
Simplify: w+8=7 w + 8 = 7
Subtract 8 from both sides: w=78 w = 7 - 8
Simplify: w=1 w = -1

STEP 8

The second equation has a specific solution: w=1 w = -1 .
The solutions are:
1. First equation: No solution
2. Second equation: w=1 w = -1

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